Advertisements
Advertisements
प्रश्न
State the correction if the positive error is 7 divisions when the least count is 0.01 cm.
Advertisements
उत्तर
When positive error is 7 divisions and L.C. is 0.01 cm
Then correction = – (+ 7 × L.C.)
= −7 × 0.01 cm
= – 0.07 cm
APPEARS IN
संबंधित प्रश्न
What is meant by zero error of vernier callipers ? How is it determined? Draw neat diagrams to explain it. How is it taken in account to get the correct measurement?
Name the instrument which has the least count
0.1 mm
The pitch of a screw gauge is 1 mm and the circular scale has 100 divisions. In measurement of the diameter of a wire, the main scale reads 2 mm and 45th mark on the circular scale coincides with the base line. Find
(i) The least count and
(ii) The diameter of the wire.
The final result of the calculation in an experiment is 125,347,200. Express the number in term of significant place when accuracy is between 1 and 10
Define the term pitch.
Explain the term least count of a screw gauge. How are they determined?
In the following figure, the pitch of the screw is 1 mm. Calculate:
(i) the least count of screw gauge and
(ii) the reading represented in the figure.
What is the least count in the case of the following instrument?
Spring balance
An instrument that is used to measure the diameter of a cricket ball is ______.
In a vernier calliper, (N + 1) divisions of the vernier scale coincide with N divisions of the main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is ______.
