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State Raoult’S Law for the Solution Containing Volatile Components - Chemistry

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प्रश्न

State Raoult’s law for the solution containing volatile components

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उत्तर

Raoult’s law: In a solution, the vapour pressure of a component at a given temperature is equal to the mole fraction of that component in the solution multiplied by the vapour pressure of that component in the pure state.

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2014-2015 (March) Panchkula Set 1

संबंधित प्रश्‍न

What type of deviation is shown by a mixture of ethanol and acetone? Give reason.


Vapour pressure of pure water at 298 K is 23.8 mm Hg. 50 g of urea (NH2CONH2) is dissolved in 850 g of water. Calculate the vapour pressure of water for this solution and its relative lowering.


100 g of liquid A (molar mass 140 g mol−1) was dissolved in 1000 g of liquid B (molar mass 180 g mol−1). The vapour pressure of pure liquid B was found to be 500 torr. Calculate the vapour pressure of pure liquid A and its vapour pressure in the solution if the total vapour pressure of the solution is 475 Torr.


For the reaction :

\[\ce{2NO_{(g)} ⇌ N2_{(g)} + O2_{(g)}}\];

ΔH = -heat

K= 2.5 × 10at 298K

What will happen to the concentration of Nif :

(1) Temperature is decreased to 273 K.

(2) The pressure is reduced


Raoult’s law states that for a solution of volatile liquids the partial pressure of each component in the solution is ____________.


Minimum boiling azeotrope is formed by the solution which showed


Considering the formation, breaking and strength of hydrogen bond, predict which of the following mixtures will show a positive deviation from Raoult’s law?


On the basis of information given below mark the correct option.

(A) In bromoethane and chloroethane mixture intermolecular interactions of A–A and B–B type are nearly same as A–B type interactions.

(B) In ethanol and acetone mixture A–A or B–B type intermolecular interactions are stronger than A–B type interactions.

(C) In chloroform and acetone mixture A–A or B–B type intermolecular interactions are weaker than A–B type interactions.


Using Raoult’s law explain how the total vapour pressure over the solution is related to mole fraction of components in the following solutions.

\[\ce{NaCl(s) and H2O(l)}\]


The vapour pressure of pure liquid X and pure liquid Y at 25°C are 120 mm Hg and 160 mm Hg respectively. If equal moles of X and Y are mixed to form an ideal solution, calculate the vapour pressure of the solution.


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