मराठी

State Newton's second law of motion.A body of mass 400 g is resting on a frictionless table. Find the acceleration of the body when acted upon by a force of 0.02 N.

Advertisements
Advertisements

प्रश्न

State Newton's second law of motion.
A body of mass 400 g is resting on a frictionless table. Find the acceleration of the body when acted upon by a force of 0.02 N.

टीपा लिहा
Advertisements

उत्तर

According to Newton's second law of motion, when a force acts on a body, the rate of change in momentum of a body equals the product of the mass of the body and acceleration produced in it due to that force, provided the mass remains constant.
Mass of body = 400 g = 0.4kg
Force applied on body = 0.02 N
Acceleration = force/mass = 0.02/0.4 = 0.05 ms-2.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Laws of Motion - Exercise 3 [पृष्ठ १३०]

APPEARS IN

फ्रँक Physics [English] Class 9 ICSE
पाठ 3 Laws of Motion
Exercise 3 | Q 54 | पृष्ठ १३०

संबंधित प्रश्‍न

A body of mass 0.40 kg moving initially with a constant speed of 10 m s–1 to the north is subject to a constant force of 8.0 N directed towards the south for 30 s. Take the instant the force is applied to be t = 0, the position of the body at that time to be x = 0, and predict its position at t = –5 s, 25 s, 100 s.


A monkey of mass 40 kg climbs on a rope in given Figure which can stand a maximum tension of 600 N. In which of the following cases will the rope break: the monkey

(a) climbs up with an acceleration of 6 m s–2

(b) climbs down with an acceleration of 4 m s–2

(c) climbs up with a uniform speed of 5 m s–1

(d) falls down the rope nearly freely under gravity?

(Ignore the mass of the rope).


You are travelling in a car. The driver suddenly applies the brakes and you are pushed forward. Why does this happen?


A particle of mass 50 g moves in a straight line. The variation of speed with time is shown in the following figure. Find the force acting on the particle at t = 2, 4 and 6 seconds.


Find the acceleration of the block of mass M in the situation shown in the following figure. All the surfaces are frictionless and the pulleys and the string are light.


The unit of linear momentum is :


The linear momentum of a body of mass m moving with velocity v is  : 


A pebble is dropped freely in a well from its top. It takes 20 s for the pebble to reach the water surface in the well. Taking g = 10 m s-2 and speed of sound = 330 m s-1. Find : The depth of water surface


A stone is thrown vertically upward with a velocity of 9.8 m/s. When will it reach the ground?


As shown in figure, a 70 kg garden roller is pushed with a force of F = 200 N at an angle of 30° with horizontal. The normal reaction on the roller is: (Given: g = 10 ms−2)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×