मराठी

Solve the following Linear Programming Problems graphically: Maximise Z = 3x + 2y subject to x + 2y ≤ 10, 3x + y ≤ 15, x, y ≥ 0.

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प्रश्न

Solve the following Linear Programming Problems graphically:

Maximise Z = 3x + 2y

subject to x + 2y ≤ 10, 3x + y ≤ 15, x, y ≥ 0.

बेरीज
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उत्तर

The system of constraints is

x + 2y ≤ 10                   ....(i)

3x + y ≤ 15                   ....(ii)

and x, y ≥ 0                 ....(iii)

Let l1 : x + 2y = 10

l2 : 3x + y =15

The shaded region in the figure is the feasible region determined by the system of constraints (i) to (iii).

It is observed that the feasible region OCEB is bounded.

Thus, we use the Corner Point Method to determine the maximum value of Z.

We have: Z = 3x + 2y                   ....(iv)

The coordinates of O, C, E and B are (0, 0) (5, 0), (4, 3) (solving x + 2y = 10, 3x + y = 15) and (0, 5) respectively.

Corner point Corresponding values of Z
(0, 0) 0
(5, 0) 15
(4, 3) 18 (Maximum)
(0, 5) 10

Hence Zmax = 18 at (4, 3).

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पाठ 12: Linear Programming - Exercise 12.1 [पृष्ठ ५१४]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 12 Linear Programming
Exercise 12.1 | Q 5 | पृष्ठ ५१४

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