मराठी

Show that the minimum of Z occurs at more than two points. Minimise and Maximise Z = 5x + 10 y subject to x + 2y ≤ 120, x + y ≥ 60, x – 2y ≥ 0, x, y ≥ 0.

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प्रश्न

Show that the minimum of Z occurs at more than two points.

Minimise and Maximise Z = 5x + 10 y

subject to x + 2y ≤ 120, x + y ≥ 60, x – 2y ≥ 0, x, y ≥ 0.

बेरीज
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उत्तर

The system of constraints is:

x + 2y ≤ 120             ...(i)

x + y ≥ 60               ....(ii)

x - 2y ≥ 0              ....(iii)

and x, y ≥ 0             ....(iv)

Let l1 : x + 2y = 120

l2 : x + y = 60

l3 : x - 2y = 0

It is observed that the feasible region CADE is bounded.

The coordinates of C, A, D, E are (60, 0), (120, 0), (60, 30), (40, 20) respectively.

Thus, we use the Corner Point Method to determine the maximum and minimum values of Z.

We have : Z = 5x + l0y

Corner Point Corresponding values of Z
(60, 0) 300 (Minimum)
(120, 0) 600
(60, 30) 600
(40, 20) 400

Hence Zmin = 300 at (60, 0) and Zmax = 600 at all points on the line segment joining the points (120, 0) and (60, 30).

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पाठ 12: Linear Programming - Exercise 12.1 [पृष्ठ ५१४]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 12 Linear Programming
Exercise 12.1 | Q 7 | पृष्ठ ५१४

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