Advertisements
Advertisements
प्रश्न
Solve for x: `("log"125)/("log"5)` = logx
Advertisements
उत्तर
`("log"125)/("log"5)` = logx
⇒ `("log"5^3)/("log"5)` = logx
⇒ `(3"log"5)/("log"5)` = logx
⇒ 3 = logx
⇒ 3log10 = log x ...(since log 10 = 1)
⇒ log 103 = logx
∴ x = 103
= 1000
APPEARS IN
संबंधित प्रश्न
If `3/2 log a + 2/3` log b - 1 = 0, find the value of a9.b4 .
Solve for x and y ; if x > 0 and y > 0 ; log xy = log `x/y` + 2 log 2 = 2.
Show that : loga m ÷ logab m + 1 + log ab
If log2(x + y) = log3(x - y) = `log 25/log 0.2`, find the values of x and y.
Given : `log x/ log y = 3/2` and log (xy) = 5; find the value of x and y.
Given log10x = 2a and log10y = `b/2`. Write 102b + 1 in terms of y.
Evaluate : `( log _5^8 )/(( log_25 16 ) xx ( log_100 10))`
Evaluate: `(log_5 8)/(log_25 16 xx Log_100 10)`
Solve for x: log (x + 5) = 1
If a = log 20 b = log 25 and 2 log (p - 4) = 2a - b, find the value of 'p'.
