Advertisements
Advertisements
प्रश्न
If `3/2 log a + 2/3` log b - 1 = 0, find the value of a9.b4 .
Advertisements
उत्तर
`3/2 log a + 2/3` log b - 1 = 0
⇒ `log a^(3/2) + log b^(2/3)` = 1
⇒ log`( a^(3/2) xx b^(2/3)) = 1`
⇒ log`( a^(3/2) xx b^(2/3)) = log 10`
⇒ `( a^(3/2) xx b^(2/3))` = 10
⇒ `( a^(3/2) xx b^(2/3))^6 = 10^6`
⇒ a9 . b4 = 106
APPEARS IN
संबंधित प्रश्न
If log2(x + y) = log3(x - y) = `log 25/log 0.2`, find the values of x and y.
Given : `log x/ log y = 3/2` and log (xy) = 5; find the value of x and y.
Given log10x = 2a and log10y = `b/2`. Write 102b + 1 in terms of y.
Given log10x = 2a and log10y = `b/2. "If" log_10^p = 3a - 2b`, express P in terms of x and y.
Solve the following:
log (x + 1) + log (x - 1) = log 48
Solve for x: `("log"125)/("log"5)` = logx
State, true of false:
If `("log"49)/("log"7)` = log y, then y = 100.
If log 3 m = x and log 3 n = y, write down
`3^(1-2y+3x)` in terms of m an n
Express the following in a form free from logarithm:
`2"log" x + 1/2"log" y` = 1
Prove that log 10 125 = 3 (1 - log 10 2)
