मराठी

Sin (tan–1 x), |x| < 1 is equal to ______. - Mathematics

Advertisements
Advertisements

प्रश्न

sin (tan–1 x), |x| < 1 is equal to ______.

पर्याय

  • `x/(sqrt(1-x^2))`

  • `1/sqrt(1-x^2)`

  • `1/sqrt(1+x^2)`

  • `x/(sqrt(1+ x^2))`

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

sin (tan–1 x), |x| < 1 is equal to `bbunderline (x/(sqrt(1+ x^2)))`.

Explanation:

Let tan1 x = θ 

= x = tan θ, where `θ ∈ (- pi/2, pi/2)`

∴ sin (tan–1 x) = sin θ

Now, sin θ = `1/("cosec" θ)`

= `1/sqrt(1+cot^2θ)`

= `1/sqrt(1+ 1/tan^2θ)`

= `x/(sqrt(x^2 + 1)`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Inverse Trigonometric Functions - Exercise 2.3 [पृष्ठ ५२]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 2 Inverse Trigonometric Functions
Exercise 2.3 | Q 15 | पृष्ठ ५२

संबंधित प्रश्‍न

 

Prove that:

`tan^(-1)""1/5+tan^(-1)""1/7+tan^(-1)""1/3+tan^(-1)""1/8=pi/4`

 

Prove the following:

3 sin−1 x = sin−1 (3x − 4x3), `x ∈ [-1/2, 1/2]`


Write the function in the simplest form: `tan^(-1)  1/(sqrt(x^2 - 1)), |x| > 1`


Write the following function in the simplest form:

`tan^(-1) (sqrt((1-cos x)/(1 + cos x)))`, 0 < x < π


Write the following function in the simplest form:

`tan^(-1)  x/(sqrt(a^2 - x^2))`, |x| < a


Find the value of the following:

`tan^-1 [2 cos (2  sin^-1  1/2)]`


Find the value of the following:

`tan  1/2 [sin^(-1)  (2x)/(1+ x^2) + cos^(-1)  (1-y^2)/(1+y^2)]`, |x| < 1, y > 0 and xy < 1


Prove that:

`cos^(-1)  4/5 + cos^(-1)  12/13 = cos^(-1)  33/65`


Prove `(9pi)/8 - 9/4  sin^(-1)  1/3 = 9/4 sin^(-1)  (2sqrt2)/3`


Solve the following equation:

2 tan−1 (cos x) = tan−1 (2 cosec x)


Prove that `tan {pi/4 + 1/2 cos^(-1)  a/b} + tan {pi/4 - 1/2 cos^(-1)  a/b} = (2b)/a`


Find the value, if it exists. If not, give the reason for non-existence

`sin^-1 [sin 5]`


Find the value of `sin^-1[cos(sin^-1 (sqrt(3)/2))]`


Find the value of  `tan(sin^-1  3/5 + cot^-1  3/2)`


Prove that `sin^-1  3/5 - cos^-1  12/13 = sin^-1  16/65`


Solve: `tan^-1x = cos^-1  (1 - "a"^2)/(1 + "a"^2) - cos^-1  (1 - "b"^2)/(1 + "b"^2), "a" > 0, "b" > 0`


Choose the correct alternative:

`tan^-1 (1/4) + tan^-1 (2/9)` is equal to


Choose the correct alternative:

sin–1(2 cos2x – 1) + cos1(1 – 2 sin2x) =


Choose the correct alternative:

If `cot^-1(sqrt(sin alpha)) + tan^-1(sqrt(sin alpha))` = u, then cos 2u is equal to


Evaluate tan (tan–1(– 4)).


Evaluate: `tan^-1 sqrt(3) - sec^-1(-2)`.


Evaluate `cos[sin^-1  1/4 + sec^-1  4/3]`


Prove that cot–17 + cot–18 + cot–118 = cot–13


If α ≤ 2 sin–1x + cos–1x ≤ β, then ______.


Evaluate `cos[cos^-1 ((-sqrt(3))/2) + pi/6]`


Prove that `tan^-1 ((sqrt(1 + x^2) + sqrt(1 - x^2))/((1 + x^2) - sqrt(1 - x^2))) = pi/2 + 1/2 cos^-1x^2`


`"cot" (pi/4 - 2  "cot"^-1  3) =` ____________.


`"tan"^-1 1 + "cos"^-1 ((-1)/2) + "sin"^-1 ((-1)/2)`


The value of expression 2 `"sec"^-1  2 + "sin"^-1 (1/2)`


If tan-1 2x + tan-1 3x = `pi/4,` then x is ____________.


If `"tan"^-1 2  "x + tan"^-1 3  "x" = pi/4`, then x is ____________.


`"tan" (pi/4 + 1/2 "cos"^-1 "x") + "tan" (pi/4 - 1/2 "cos"^-1 "x") =` ____________.


`"tan"^-1 1/3 + "tan"^-1 1/5 + "tan"^-1 1/7 + "tan"^-1 1/8 =` ____________.


`"sin"^-1 (1 - "x") - 2  "sin"^-1 "x" = pi/2`


Solve for x : `{"x cos" ("cot"^-1 "x") + "sin" ("cot"^-1 "x")}^2` = `51/50


What is the simplest form of `tan^-1  sqrt(1 - x^2 - 1)/x, x ≠ 0`


`sin^-1(1 - x) - 2sin^-1 x = pi/2`, tan 'x' is equal to


The value of cosec `[sin^-1((-1)/2)] - sec[cos^-1((-1)/2)]` is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×