मराठी

Prove `2 Tan^(-1) 1/2 + Tan^(-1) 1/7 = Tan^(-1) 31/17` - Mathematics

Advertisements
Advertisements

प्रश्न

Prove `2 tan^(-1)  1/2 + tan^(-1)  1/7 = tan^(-1)  31/17`

Advertisements

उत्तर

Tp prove `2 tan^(-1)  1/2 + tan^(-1)  1/7 = tan^(-1)  31/17`

L.H.S = `2tan^(-1)  1/2 + tan^(-1)  1/7`

= `tan^(-1)   (2. 1/2)/(1-(1/2)^2) + tan^(-1)  1/7`   `   "                   "[2 tan^(-1) x = tan^(-1)  (2x)/(1-x^2)]`

`= tan^(-1)  1/ ((3/4)) + tan^(-1)  1/7`

`= tan^(-1)  4/3 + tan^(-1)  1/7`

= `tan^(-1)  (4/3 + 1/7) /(1 - 4/3. 1/7)`  `[tan^(-1) x + tan^(-1) y = tan^(-1)  (x + y)/(1 -  xy)]`

`= tan^(-1)  ((28+3)/21)/((21-4)/21)`

= `tan^(-1)  31/17` = R.H.S

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Inverse Trigonometric Functions - Exercise 2.2 [पृष्ठ ४७]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 2 Inverse Trigonometric Functions
Exercise 2.2 | Q 4 | पृष्ठ ४७

संबंधित प्रश्‍न

Find the value of the given expression.

`tan(sin^(-1)  3/5 + cot^(-1)  3/2)`


Prove that:

`cos^(-1)  12/13 + sin^(-1)  3/5 = sin^(-1)  56/65`


Find the value, if it exists. If not, give the reason for non-existence

`tan^-1(sin(- (5pi)/2))`


Find the value of the expression in terms of x, with the help of a reference triangle

`tan(sin^-1(x + 1/2))`


Prove that `tan^-1x + tan^-1y + tan^-1z = tan^-1[(x + y + z - xyz)/(1 - xy - yz - zx)]`


Solve: `2tan^-1 (cos x) = tan^-1 (2"cosec"  x)`


Find the number of solutions of the equation `tan^-1 (x - 1) + tan^-1x + tan^-1(x + 1) = tan^-1(3x)`


Choose the correct alternative:

`tan^-1 (1/4) + tan^-1 (2/9)` is equal to


Choose the correct alternative:

`sin^-1 (tan  pi/4) - sin^-1 (sqrt(3/x)) = pi/6`. Then x is a root of the equation


Choose the correct alternative:

If `cot^-1(sqrt(sin alpha)) + tan^-1(sqrt(sin alpha))` = u, then cos 2u is equal to


Choose the correct alternative:

If `sin^-1x + cot^-1 (1/2) = pi/2`, then x is equal to


Evaluate tan (tan–1(– 4)).


Prove that `2sin^-1  3/5 - tan^-1  17/31 = pi/4`


Prove that cot–17 + cot–18 + cot–118 = cot–13


Solve the equation `sin^-1 6x + sin^-1 6sqrt(3)x = - pi/2`


Show that `tan(1/2 sin^-1  3/4) = (4 - sqrt(7))/3` and justify why the other value `(4 + sqrt(7))/3` is ignored?


If a1, a2, a3,...,an is an arithmetic progression with common difference d, then evaluate the following expression.

`tan[tan^-1("d"/(1 + "a"_1 "a"_2)) + tan^-1("d"/(21 + "a"_2 "a"_3)) + tan^-1("d"/(1 + "a"_3 "a"_4)) + ... + tan^-1("d"/(1 + "a"_("n" - 1) "a""n"))]`


If 3 tan–1x + cot–1x = π, then x equals ______.


The number of real solutions of the equation `sqrt(1 + cos 2x) = sqrt(2) cos^-1 (cos x)` in `[pi/2, pi]` is ______.


If cos–1x > sin–1x, then ______.


The value of cot–1(–x) for all x ∈ R in terms of cot–1x is ______.


If `"sec" theta = "x" + 1/(4 "x"), "x" in "R, x" ne 0,`then the value of  `"sec" theta + "tan" theta` is ____________.


The value of `"tan"^ -1 (3/4) + "tan"^-1 (1/7)` is ____________.


`"cot" (pi/4 - 2  "cot"^-1  3) =` ____________.


If x = a sec θ, y = b tan θ, then `("d"^2"y")/("dx"^2)` at θ = `π/6` is:


Solve for x : `"sin"^-1  2"x" + "sin"^-1  3"x" = pi/3`


The value of `"tan"^-1 (3/4) + "tan"^-1 (1/7)` is ____________.


If `"tan"^-1 2  "x + tan"^-1 3  "x" = pi/4`, then x is ____________.


`"tan"^-1 1/3 + "tan"^-1 1/5 + "tan"^-1 1/7 + "tan"^-1 1/8 =` ____________.


`"sin"^-1 (1 - "x") - 2  "sin"^-1 "x" = pi/2`


Solve for x : `{"x cos" ("cot"^-1 "x") + "sin" ("cot"^-1 "x")}^2` = `51/50


What is the value of cos (sec–1x + cosec–1x), |x| ≥ 1


Find the value of `cos^-1 (1/2) + 2sin^-1 (1/2) ->`:-


`tan^-1 sqrt3 - cot^-1 (- sqrt3)` is equal to ______.


If sin–1x + sin–1y + sin–1z = π, show that `x^2 - y^2 - z^2 + 2yzsqrt(1 - x^2) = 0`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×