मराठी

Sin { 2 Cos − 1 ( − 3 5 ) } is Equal to (A) 6 25 (B) 24 25 (C) 4 5 (D) − 24 25 - Mathematics

Advertisements
Advertisements

प्रश्न

sin \[\left\{ 2 \cos^{- 1} \left( \frac{- 3}{5} \right) \right\}\]  is equal to

 

पर्याय

  • `6/25`

  • `24/25`

  • `4/5`

  • `-24/25`

MCQ
Advertisements

उत्तर

(d) `-24/25`

Let \[\cos^{- 1} \left( - \frac{3}{5} \right) = x, 0 \leq x \leq \pi\]
Then,
`cosx=-3/5`
\[\therefore \sin{x} = \sqrt{1 - \cos^2 x} = \sqrt{1 - \left( - \frac{3}{5} \right)^2} = \sqrt{\frac{16}{25}} = \frac{4}{5}\]
Now,
\[\sin\left\{ 2 \cos^{- 1} \left( - \frac{3}{5} \right) \right\} = \sin\left( 2x \right)\]
\[ = 2\sin{x} \cos{x}\]
\[ = 2 \times \frac{4}{5} \times \frac{- 3}{5}\]
\[ = - \frac{24}{25}\]



shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Inverse Trigonometric Functions - Exercise 4.16 [पृष्ठ १२१]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.16 | Q 21 | पृष्ठ १२१

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

If (tan1x)2 + (cot−1x)2 = 5π2/8, then find x.


 

If `tan^(-1)((x-2)/(x-4)) +tan^(-1)((x+2)/(x+4))=pi/4` ,find the value of x

 

Find the domain of `f(x)=cos^-1x+cosx.`


`sin^-1(sin  (17pi)/8)`


Evaluate the following:

`cos^-1{cos  (5pi)/4}`


Evaluate the following:

`tan^-1(tan  pi/3)`


Evaluate the following:

`sec^-1(sec  (2pi)/3)`


Evaluate the following:

`sec^-1(sec  (7pi)/3)`


Evaluate the following:

`sec^-1(sec  (13pi)/4)`


Evaluate the following:

`cosec^-1(cosec  (3pi)/4)`


Evaluate the following:

`cosec^-1(cosec  (11pi)/6)`


Evaluate the following:

`cot^-1(cot  (19pi)/6)`


Evaluate the following:

`sin(cos^-1  5/13)`


Prove the following result-

`tan^-1  63/16 = sin^-1  5/13 + cos^-1  3/5`


Evaluate:

`cos(tan^-1  3/4)`


Evaluate: `sin{cos^-1(-3/5)+cot^-1(-5/12)}`


If `cot(cos^-1  3/5+sin^-1x)=0`, find the values of x.


If `(sin^-1x)^2+(cos^-1x)^2=(17pi^2)/36,`  Find x


`sin^-1x=pi/6+cos^-1x`


Solve the following equation for x:

 cot−1x − cot−1(x + 2) =`pi/12`, > 0


Evaluate the following:

`sin(1/2cos^-1  4/5)`


Prove that:

`2sin^-1  3/5=tan^-1  24/7`


`sin^-1  4/5+2tan^-1  1/3=pi/2`


`2tan^-1  1/5+tan^-1  1/8=tan^-1  4/7`


Solve the following equation for x:

`tan^-1((2x)/(1-x^2))+cot^-1((1-x^2)/(2x))=(2pi)/3,x>0`


If x < 0, then write the value of cos−1 `((1-x^2)/(1+x^2))` in terms of tan−1 x.


What is the value of cos−1 `(cos  (2x)/3)+sin^-1(sin  (2x)/3)?`


Write the range of tan−1 x.


Write the value ofWrite the value of \[2 \sin^{- 1} \frac{1}{2} + \cos^{- 1} \left( - \frac{1}{2} \right)\]


Evaluate: \[\sin^{- 1} \left( \sin\frac{3\pi}{5} \right)\]


Write the principal value of \[\cos^{- 1} \left( \cos680^\circ  \right)\]


The positive integral solution of the equation
\[\tan^{- 1} x + \cos^{- 1} \frac{y}{\sqrt{1 + y^2}} = \sin^{- 1} \frac{3}{\sqrt{10}}\text{ is }\]


If θ = sin−1 {sin (−600°)}, then one of the possible values of θ is

 


If 4 cos−1 x + sin−1 x = π, then the value of x is

 


In a ∆ ABC, if C is a right angle, then
\[\tan^{- 1} \left( \frac{a}{b + c} \right) + \tan^{- 1} \left( \frac{b}{c + a} \right) =\]

 

 


Find the simplified form of `cos^-1 (3/5 cosx + 4/5 sin x)`, where x ∈ `[(-3pi)/4, pi/4]`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×