मराठी

Side of an Equilateral Triangle Expands at the Rate of 2 Cm/Sec. the Rate of Increase of Its Area When Each Side is 10 Cm is (A) 10 √ 2 C M 2 / Sec

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प्रश्न

Side of an equilateral triangle expands at the rate of 2 cm/sec. The rate of increase of its area when each side is 10 cm is

पर्याय

  • \[10\sqrt{2} \ {cm}^2 /\sec\]

  • \[10\sqrt{3} {cm}^2 /\sec\]

  • 10 cm2/sec

  • 5 cm2/sec

MCQ
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उत्तर

\[10\sqrt{3} \ {cm}^2 /\sec\]

\[\text { Letxbe the side andAbe the area of the equilateral triangle at any timet.Then },\]
\[A = \frac{\sqrt{3}}{4} x^2 \]
\[ \Rightarrow \frac{dA}{dt} = 2 \times \frac{\sqrt{3}}{4} x^{} \frac{dx}{dt}\]
\[\Rightarrow\frac{dA}{dt}=\frac{\sqrt{3}}{2}\times2\times10\]
\[\Rightarrow\frac{dA}{dt}=10\sqrt{3} \ {cm}^2 /sec\]

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पाठ 12: Derivative as a Rate Measurer - Exercise 13.4 [पृष्ठ २४]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 12 Derivative as a Rate Measurer
Exercise 13.4 | Q 2 | पृष्ठ २४

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