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Show that sin8xcosx-sin6xcos3xcos2xcosx-sin3xsin4x = tan 2x

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प्रश्न

Show that `(sin 8x cos x - sin 6x cos 3x)/(cos 2x cos x - sin 3x sin 4x)` = tan 2x

बेरीज
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उत्तर

 `(sin 8x cos x - sin 6x cos 3x)/(cos 2x cos x - sin 3x sin 4x) = (1/2 [sin 9x + sin 7x] - 1/2 [sin 9x + sin 3x])/(1/2 [cos 3x + cos x] - 1/2 [cos x - cos 3x])`

= `(sin 9x + sin 7x - sin 9x - sin 3x)/(cos 3x + cos x - cos x + cos 7x)`

= `(sin 7x - sin 3x)/(cos 3x + cos 7x)`

= `(sin 7x - sin 3x)/(cos 7x + cos 3x)`

= `(2cos((7x + 3x)/2) * sin ((7x  3x)/2))/(2cos((7x + 3x)/2) * cos((7x - 3x)/2)`

= `(2 cos 5x * sin 2x)/(2 cos 5x * cos 2x)`

= `(sin 2x)/(cos 2x)`

= tan 2x

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Trigonometric Functions and Their Properties
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - Exercise 3.6 [पृष्ठ १२१]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 3 Trigonometry
Exercise 3.6 | Q 5 | पृष्ठ १२१

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