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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान इयत्ता ११

Find the value of cos 105°.

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प्रश्न

Find the value of cos 105°.

बेरीज
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उत्तर

cos 105° = cos(60° + 45°)

= [cos 60° cos 45° – sin 60° sin 45°]

= `[1/2*1/sqrt2-sqrt(3)/2*1/sqrt(2)]`

= `(1-sqrt3)/(2sqrt2)`

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Trigonometric Functions and Their Properties
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - Exercise 3.4 [पृष्ठ १०९]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 3 Trigonometry
Exercise 3.4 | Q 5. (i) | पृष्ठ १०९

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