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If sin x = 1517 and cos y = 1213,0<x<π2,0<y<π2 find the value of sin(x + y) - Mathematics

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प्रश्न

If sin x = `15/17` and cos y = `12/13, 0 < x < pi/2, 0 < y < pi/2` find the value of sin(x + y)

बेरीज
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उत्तर

Given sin x = `15/17, 0 < x < pi/2`

We have cos2x + sin2x = 1

∴ cos2x = 1 – sin2x

= `1 - (15/17)^2`

= `1 - 225/289`

cos2x = `(289 - 225)/289 = 64/289`

cos x = `+-  sqrt(64/289)`

= `+-  8/17`

Given that `0 < x < pi/2`, that is x lies in the first quadrant

∴ cos x is positive.

cos x = `8/17`

Also given cos y = `12/13, 0 < x < pi/2`

We have cos2y + sin2y = 1

sin2y = 1 – cos2y

sin2y = `1 - (12/13)^2 = 1 - 14/169`

sin2y = `(169 - 144)/169 = 25/169`

sin y = `+-  sqrt(25/169) = +-  5/13`

Since `0 < y < pi/2, y lies in the first quadrant sin y is positive.

∴ sin y = `5/13`

sin x = `15/17`

sin y = `5/13`

cos x = `8/17`

cos y = `12/13`

sin(x + y) = sin x cos y + cos x sin y

= `15/17 * 12/13 + 8/17 * 5/13`

sin(x + y) = `180/221 + 40/221`

= `220/221`

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Trigonometric Functions and Their Properties
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - Exercise 3.4 [पृष्ठ १०९]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 3 Trigonometry
Exercise 3.4 | Q 1. (i) | पृष्ठ १०९

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