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Prove that sin 105° + cos 105° = cos 45°

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प्रश्न

Prove that sin 105° + cos 105° = cos 45°

बेरीज
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उत्तर

sin 105° + cos 105° = sin(90° + 15°) + cos(90° + 15°)

= cos 15° – sin 15°

= cos(45° – 30°) sin(45° – 30°)

= (cos 45° . cos30° + sin 45° sin 30°) – (sin 45° cos 30° – cos 45° sin 30°)

= `(1/sqrt(2) * sqrt(3)/2 + 1/sqrt(2) * 1/sqrt(2)) - (1/sqrt(2) * sqrt(3)/2 - 1/sqrt(2) * 1/sqrt(2))`

= `sqrt(3)/(2sqrt(2)) + 1/(2sqrt(2)) - sqrt(3)/(2sqrt(2)) + 1/(2sqrt(2))`

= `2/(2sqrt(2))`

= `1/sqrt(2)`

= cos 45°

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Trigonometric Functions and Their Properties
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - Exercise 3.4 [पृष्ठ १०९]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 3 Trigonometry
Exercise 3.4 | Q 11 | पृष्ठ १०९

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