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Prove that sin 75° – sin 15° = cos 105° + cos 15° - Mathematics

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प्रश्न

Prove that sin 75° – sin 15° = cos 105° + cos 15°

बेरीज
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उत्तर

R.H.S = cos 105° + cos 15°

= cos(90° + 15°) + cos(90° – 75°)

= – sin 15° + sin 75°

= sin 75° – sin 15°

= L.H.S

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Trigonometric Functions and Their Properties
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - Exercise 3.4 [पृष्ठ १०९]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 3 Trigonometry
Exercise 3.4 | Q 12 | पृष्ठ १०९

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