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Express the following as a productsin 75° sin 35° - Mathematics

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प्रश्न

Express the following as a product
sin 75° sin 35°

बेरीज
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उत्तर

We know sin C – sin D = `2 cos  ("C" + "D")/2 * sin  ("C" - "D")/2`

Take C = 75°, D = 35°

sin 75° – sin 35° = `2cos((75^circ + 35^circ)/2) * sin((75^circ - 35^circ)/2)`

sin 75° – sin 35° = `2cos(110^circ/2) * sin(40^circ/2)`

sin 75° – sin 35° = 2 cos 55° sin 20°

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Trigonometric Functions and Their Properties
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - Exercise 3.6 [पृष्ठ १२१]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 3 Trigonometry
Exercise 3.6 | Q 2. (i) | पृष्ठ १२१

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