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Prove that sin(A + B) sin(A – B) = sin2A – sin2B

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प्रश्न

Prove that sin(A + B) sin(A – B) = sin2A – sin2B

बेरीज
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उत्तर

L.H.S = sin(A + B) sin(A – B)

= (sin A cos B + cos A sin B) (sin A cos B – cos A sin B)

= sin2A cos2B – cos2A sin2B

= sin2A(1 – sin2B) – (1 – sin2A) sin2B

= sin2A – sin2A sin2B – sin2B + sin2A sin2B

= sin2A – sin2B

= R.H.S

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Trigonometric Functions and Their Properties
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - Exercise 3.4 [पृष्ठ १०९]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 3 Trigonometry
Exercise 3.4 | Q 17. (i) | पृष्ठ १०९

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