Advertisements
Advertisements
प्रश्न
Radioactive decay follows first-order kinetics. The initial amount of two radioactive elements X and Y is 1 gm each. What will be the ratio of X and Y after two days if their half-lives are 12 hours and 16 hours respectively?
Advertisements
उत्तर
For first-order reaction
half life of X = 12 hours
2 days = 48 hours means 4 half lives,
Amount of X left = `1/16` of initial value
half life of Y = 16 hours
2 days = 48 hours means 3 half lives,
Amount left = `1/8` of initial value
Ratio of X : Y = 1 : 2
APPEARS IN
संबंधित प्रश्न
In a pseudo first order reaction in water, the following results were obtained:
| t/s | 0 | 30 | 60 | 90 |
| [A]/mol L−1 | 0.55 | 0.31 | 0.17 | 0.085 |
Calculate the average rate of reaction between the time interval 30 to 60 seconds.
The rate constant for a first order reaction is 60 s−1. How much time will it take to reduce the initial concentration of the reactant to its `1/16`th value?
Define order of reaction. How does order of a reaction differ from molecularity for a complex reaction?
Straight line graph for first order reaction is obtained between ____________.
Which of the following graphs is correct for a first order reaction?
With the help of an example explain what is meant by pseudo first order reaction.
For a first order reaction, the ratio of the time for 75% completion of a reaction to the time for 50% completion is ______. (Integer answer)
The slope in the plot of `log ["R"]_0/(["R"])` Vs. time for a first-order reaction is ______.
The following data were obtained during the decomposition of SO2Cl2 at the constant volume. SO2Cl2 →SO2(g) + Cl2(g)
| Time (s) | Total Pressure (bar) |
| 0 | 0.5 |
| 100 | 0.6 |
Calculate the rate constant of the reaction.
Write the unit of rate constant [k] for the first order reaction.
