मराठी

Prove that X2 – Y2 = C(X2 + Y2)2 is the General Solution of the Differential Equation (X3 – 3xy2)Dx = (Y3 – 3x2y)Dy, Where C is Parameter

Advertisements
Advertisements

प्रश्न

Prove that x2 – y2 = c(x2 + y2)2 is the general solution of the differential equation (x3 – 3xy2)dx = (y3 – 3x2y)dy, where C is parameter

Advertisements

उत्तर

The given equation is:

(x3 – 3xy2)dx = (y3 – 3x2y)dy

`=> (dy)/(dx) = (x^3 - 3xy^2)/(y^3 - 3x^2y)`

which is a homogeneous equation.therefore substituting y=vx

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2016-2017 (March) Delhi Set 1

संबंधित प्रश्‍न

Find the particular solution of the differential equation:

2y ex/y dx + (y - 2x ex/y) dy = 0 given that x = 0 when y = 1.


Show that the given differential equation is homogeneous and solve them.

(x – y) dy – (x + y) dx = 0


Show that the given differential equation is homogeneous and solve them.

`x^2 dy/dx = x^2 - 2y^2 + xy`


Show that the given differential equation is homogeneous and solve them.

`{xcos(y/x) + ysin(y/x)}ydx = {ysin (y/x) -  xcos(y/x)}xdy`


\[\left( 1 + e^{x/y} \right) dx + e^{x/y} \left( 1 - \frac{x}{y} \right) dy = 0\]

\[x\frac{dy}{dx} = y - x \cos^2 \left( \frac{y}{x} \right)\]

(x2 + 3xy + y2) dx − x2 dy = 0


\[\left( x - y \right)\frac{dy}{dx} = x + 2y\]

(2x2 y + y3) dx + (xy2 − 3x3) dy = 0


\[x\frac{dy}{dx} - y + x \sin\left( \frac{y}{x} \right) = 0\]

Solve the following initial value problem:
\[x e^{y/x} - y + x\frac{dy}{dx} = 0, y\left( e \right) = 0\]


Solve the following initial value problem:
\[x\frac{dy}{dx} - y + x \sin\left( \frac{y}{x} \right) = 0, y\left( 2 \right) = x\]


Solve the following differential equation : \[\left[ y - x  \cos\left( \frac{y}{x} \right) \right]dy + \left[ y  \cos\left( \frac{y}{x} \right) - 2x  \sin\left( \frac{y}{x} \right) \right]dx = 0\] .


Solve the following differential equation:

`"x" sin ("y"/"x") "dy" = ["y" sin ("y"/"x") - "x"] "dx"`


Solve the following differential equation:

`(1 + 2"e"^("x"/"y")) + 2"e"^("x"/"y")(1 - "x"/"y") "dy"/"dx" = 0`


Solve the following differential equation:

`"dy"/"dx" + ("x" - "2y")/("2x" - "y") = 0`


Solve the following differential equation:

`(1 + "e"^("x"/"y"))"dx" + "e"^("x"/"y")(1 - "x"/"y")"dy" = 0`


Solve the following differential equation:

(x2 – y2)dx + 2xy dy = 0


F(x, y) = `(ycos(y/x) + x)/(xcos(y/x))` is not a homogeneous function.


F(x, y) = `(x^2 + y^2)/(x - y)` is a homogeneous function of degree 1.


A homogeneous differential equation of the `(dx)/(dy) = h(x/y)` can be solved by making the substitution.


Which differential equation is called a homogeneous differential equation?


A function \[F(x,y)\] is homogeneous of degree \[n\] when which condition holds?


If \[F(\lambda x,\lambda y)=F(x,y)\] for any non-zero constant \[\lambda\], what is the degree of \[F(x,y)\]?


What replacement obtains the final answer after using a homogeneous substitution?


For \[F(x,y)=\frac{y\cos\left(\frac{y}{x}\right)+x}{x\cos\left(\frac{y}{x}\right)}\], what is \[F(\lambda x,\lambda y)\]?


Which separable equation follows from \[x\frac{dv}{dx}=\frac{1}{\cos v}\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×