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प्रश्न
Evaluate `int_0^(3/2) |x sin pix|dx`
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उत्तर
For 0 < x < 1, `xsinpix > 0`
For 1 < x < 32, `xsinpix < 0`
So,
`int_0^(3/2) |x sin pi x|dx = int_0^1 xsin pix dx - int_1^(3/2) xsin pix dx`
Let I = ∫xsin πx dx
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