मराठी

Find the integrals of the function: sin3x+cos3xsin2xcos2x

Advertisements
Advertisements

प्रश्न

Find the integrals of the function:

`(sin^3 x + cos^3 x)/(sin^2x cos^2 x)`

बेरीज
Advertisements

उत्तर

`int (sin^3 x + cos^3 x)/(sin^2 x cos^2 x)  "dx"`

`= int sin^3x/(sin^2 x cos^2 x) + cos^3/ (sin^2 x cos^2 x) dx`

`= int (sec x tan x + cosec x cot x) dx`

= sec x - cosec x + C

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Integrals - Exercise 7.3 [पृष्ठ ३०७]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.3 | Q 17 | पृष्ठ ३०७

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Evaluate : `intsin(x-a)/sin(x+a)dx`

 


Find the integrals of the function:

sin 3x cos 4x


Find the integrals of the function:

sin x sin 2x sin 3x


Find the integrals of the function:

`(1-cosx)/(1 +  cos x)`


Find the integrals of the function:

sin4 x


Find the integrals of the function:

`(sin^2 x)/(1 + cos x)`


Find the integrals of the function:

`(cos x -  sinx)/(1+sin 2x)`


Find the integrals of the function:

tan3 2x sec 2x


Find the integrals of the function:

`1/(sin xcos^3 x)`


Find the integrals of the function:

sin−1 (cos x)


`int (sin^2x - cos^2 x)/(sin^2 x cos^2 x) dx` is equal to ______.


Find  `int dx/(x^2 + 4x + 8)`


Evaluate `int_0^(3/2) |x sin pix|dx`


Find `int((3 sin x - 2) cos x)/(13 - cos^2 x- 7 sin x) dx`


Evaluate : \[\int\limits_0^\pi \frac{x \tan x}{\sec x \cdot cosec x}dx\] .


Find `int_  (log "x")^2 d"x"`


Find: `int_  (cos"x")/((1 + sin "x") (2+ sin"x")) "dx"`


Integrate the function `cos("x + a")/sin("x + b")` w.r.t. x.


Find: `int sec^2 x /sqrt(tan^2 x+4) dx.`


Find: `int sin^-1 (2x) dx.`


Evaluate `int tan^8 x sec^4 x"d"x`


`int "dx"/(sin^2x cos^2x)` is equal to ______.


Evaluate the following:

`int ((1 + cosx))/(x + sinx) "d"x`


Evaluate the following:

`int (sinx + cosx)/sqrt(1 + sin 2x) "d"x`


Evaluate the following:

`int (sin^6x + cos^6x)/(sin^2x cos^2x) "d"x`


Evaluate the following:

`int (cosx - cos2x)/(1 - cosx) "d"x`


Evaluate the following:

`int "e"^(tan^-1x) ((1 + x + x^2)/(1 + x^2)) "d"x`


Which identity is used for \(\cos^2 x\)?


Which identity is used for the product of sine and cosine?


Using \(\cos^2 x = \frac{1+\cos 2x}{2}\), which expression is equivalent to \(\int \cos^2 x\,dx\)?


What is \(\int \cos^2 x\,dx\)?


Applying the product-to-sum identity to \(\sin 2x\cos 3x\) gives which expression?


Which procedure is recommended when an identity can simplify a complicated trigonometric expression?


After a trigonometric expression has been simplified, how should it be integrated?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×