मराठी

Find the general solution of the differential equation: (xy – x2) dy = y2 dx

Advertisements
Advertisements

प्रश्न

Find the general solution of the differential equation:

(xy – x2) dy = y2 dx

बेरीज
Advertisements

उत्तर

(xy − x2) dy = y2 dx

Divide throughout by y2 (assuming y ≠ 0) to simplify:

`(xy-x^2)/y^2 dy = dx`

`(x/y - x^2/y^2) dy = dx`

To simplify, let us introduce a substitution. Divide the entire equation by x2 (assuming x ≠ 0):

`(1/x.y/x - 1/y) dy = 1/x^2 dx`

`v = y/x` (so that y = vx and dy = v dx + x dv)

Substitute into the equation:

`(1/xv - 1/v) (v dx + xdv) = 1/x^2 dx`

`(v/x - 1/(vx) (v dx + xdv) = 1/x^2 dx)`

Simplify step by step:

Multiply and separate:

`v^2/x dx + v/x xdv - 1/(vx) vdx - 1/(vx) xdv = 1/x^2 dx`

`v^2/x dx - 1/x dx + v dv - 1/vdv = 1/x^2 dx`

Group terms involving v and x. The equation becomes:

`(v^2 - 1)/v dv = (1/x^2 - (v^2-z)/x) dx`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2022-2023 (March) Outside Delhi Set 1

संबंधित प्रश्‍न

 

Show that the differential  equation `2xydy/dx=x^2+3y^2`  is homogeneous and solve it.

 

Show that the given differential equation is homogeneous and solve them.

`y' = (x + y)/x`


Show that the given differential equation is homogeneous and solve them.

(x2 – y2) dx + 2xy dy = 0


Show that the given differential equation is homogeneous and solve them.

`x^2 dy/dx = x^2 - 2y^2 + xy`


Show that the given differential equation is homogeneous and solve them.

`x dy/dx - y +  x sin (y/x) = 0`


Show that the given differential equation is homogeneous and solve them.

`(1+e^(x/y))dx + e^(x/y) (1 - x/y)dy = 0`


A homogeneous differential equation of the from `dx/dy = h (x/y)` can be solved by making the substitution.


\[\left( 1 + e^{x/y} \right) dx + e^{x/y} \left( 1 - \frac{x}{y} \right) dy = 0\]

\[x\frac{dy}{dx} = y - x \cos^2 \left( \frac{y}{x} \right)\]

(x2 + 3xy + y2) dx − x2 dy = 0


(2x2 y + y3) dx + (xy2 − 3x3) dy = 0


Solve the following initial value problem:
(xy − y2) dx − x2 dy = 0, y(1) = 1


Solve the following initial value problem:
\[\frac{dy}{dx} = \frac{y\left( x + 2y \right)}{x\left( 2x + y \right)}, y\left( 1 \right) = 2\]

 


Solve the following initial value problem:
x (x2 + 3y2) dx + y (y2 + 3x2) dy = 0, y (1) = 1


Which of the following is a homogeneous differential equation?


Solve the following differential equation : \[\left[ y - x  \cos\left( \frac{y}{x} \right) \right]dy + \left[ y  \cos\left( \frac{y}{x} \right) - 2x  \sin\left( \frac{y}{x} \right) \right]dx = 0\] .


Solve the following differential equation:

`"x" sin ("y"/"x") "dy" = ["y" sin ("y"/"x") - "x"] "dx"`


Solve the following differential equation:

y2 dx + (xy + x2)dy = 0


Solve the following differential equation:

(x2 + 3xy + y2)dx - x2 dy = 0


Find the equation of a curve passing through `(1, pi/4)` if the slope of the tangent to the curve at any point P(x, y) is `y/x - cos^2  y/x`.


Solcve: `x ("d"y)/("d"x) = y(log y – log x + 1)`


If \[F(\lambda x,\lambda y)=F(x,y)\] for any non-zero constant \[\lambda\], what is the degree of \[F(x,y)\]?


Which dependence is checked on the right-hand side of a homogeneous differential equation?


Which substitutions are chosen for a homogeneous differential equation?


For \[F(x,y)=\frac{y\cos\left(\frac{y}{x}\right)+x}{x\cos\left(\frac{y}{x}\right)}\], what is \[F(\lambda x,\lambda y)\]?


Which separable equation follows from \[x\frac{dv}{dx}=\frac{1}{\cos v}\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×