मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

P the Average Energy in One Time Period in Simple Harmonic Motion is - Physics

Advertisements
Advertisements

प्रश्न

The average energy in one time period in simple harmonic motion is

पर्याय

  • \[\frac{1}{2}m \omega^2 A^2\]

  • \[\frac{1}{4}m \omega^2 A^2\]

  • m ω2A2

  • zero

MCQ
Advertisements

उत्तर

\[\frac{1}{2}m \omega^2 A^2\]

It is the total energy in simple harmonic motion in one time period.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 12: Simple Harmonics Motion - MCQ [पृष्ठ २५१]

APPEARS IN

एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
पाठ 12 Simple Harmonics Motion
MCQ | Q 12 | पृष्ठ २५१

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Define phase of S.H.M.


A particle executes S.H.M. with a period of 10 seconds. Find the time in which its potential energy will be half of its total energy.


A particle executing simple harmonic motion comes to rest at the extreme positions. Is the resultant force on the particle zero at these positions according to Newton's first law?


A pendulum clock gives correct time at the equator. Will it gain time or loose time as it is taken to the poles?


The motion of a particle is given by x = A sin ωt + B cos ωt. The motion of the particle is


A particle moves on the X-axis according to the equation x = A + B sin ωt. The motion is simple harmonic with amplitude


The motion of a torsional pendulum is
(a) periodic
(b) oscillatory
(c) simple harmonic
(d) angular simple harmonic


Which of the following quantities are always negative in a simple harmonic motion?

(a) \[\vec{F} . \vec{a} .\]

(b) \[\vec{v} . \vec{r} .\]

(c) \[\vec{a} . \vec{r} .\]

(d)\[\vec{F} . \vec{r} .\]


The pendulum of a certain clock has time period 2.04 s. How fast or slow does the clock run during 24 hours?


A pendulum clock giving correct time at a place where g = 9.800 m/s2 is taken to another place where it loses 24 seconds during 24 hours. Find the value of g at this new place.


A simple pendulum of length 40 cm is taken inside a deep mine. Assume for the time being that the mine is 1600 km deep. Calculate the time period of the pendulum there. Radius of the earth = 6400 km.


A simple pendulum is suspended from the roof of a school bus which moves in a horizontal direction with an acceleration a, then the time period is


What is an epoch?


Write short notes on two springs connected in parallel.


What is meant by simple harmonic oscillation? Give examples and explain why every simple harmonic motion is a periodic motion whereas the converse need not be true.


Consider the Earth as a homogeneous sphere of radius R and a straight hole is bored in it through its centre. Show that a particle dropped into the hole will execute a simple harmonic motion such that its time period is

T = `2π sqrt("R"/"g")`


The displacement of a particle is represented by the equation y = sin3ωt. The motion is ______.


The displacement of a particle varies with time according to the relation y = a sin ωt + b cos ωt.


A body having specific charge 8 µC/g is resting on a frictionless plane at a distance 10 cm from the wall (as shown in the figure). It starts moving towards the wall when a uniform electric field of 100 V/m is applied horizontally toward the wall. If the collision of the body with the wall is perfectly elastic, then the time period of the motion will be ______ s.


A weightless rigid rod with a small iron bob at the end is hinged at point A to the wall so that it can rotate in all directions. The rod is kept in the horizontal position by a vertical inextensible string of length 20 cm, fixed at its midpoint. The bob is displaced slightly, perpendicular to the plane of the rod and string. The period of small oscillations of the system in the form `(pix)/10` is ______ sec. and the value of x is ______.

(g = 10 m/s2)

 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×