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A Particle Moves on the X-axis According to the Equation X = X0 Sin2 ωT. the Motion is Simple Harmonic

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प्रश्न

A particle moves on the X-axis according to the equation x = x0 sin2 ωt. The motion is simple harmonic

पर्याय

  • with amplitude x0

  • with amplitude 2x0

  • with time period \[\frac{2\pi}{\omega}\]

  • with time period \[\frac{\pi}{\omega} .\]

MCQ
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उत्तर

with time period \[\frac{\pi}{\omega} \]

Given equation:
x = xo sin2 ωt

⇒​ \[x = \frac{x_0}{2}(\cos 2\omega t - 1)\]

Now, the amplitude of the particle is xo/2 and the angular frequency of the SHM is 2ω.

Thus, time period of the SHM = 

\[\frac{2\pi}{\text { angular frequency }} = \frac{2\pi}{2\omega} = \frac{\pi}{\omega}\]
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पाठ 12: Simple Harmonics Motion - MCQ [पृष्ठ २५२]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 12 Simple Harmonics Motion
MCQ | Q 12 | पृष्ठ २५२

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