Advertisements
Advertisements
प्रश्न
If the inertial mass and gravitational mass of the simple pendulum of length l are not equal, then the time period of the simple pendulum is
पर्याय
T = `2π sqrt(("m"_"i""l")/("m"_"g""g"))`
T = `2π sqrt(("m"_"g""l")/("m"_"i""g"))`
T = `2π "m"_"g"/"m"_"i" sqrt("l"/"g")`
T = `2π "m"_"i"/"m"_"g" sqrt("l"/"g")`
Advertisements
उत्तर
T = `2π sqrt(("m"_"i""l")/("m"_"g""g"))`
APPEARS IN
संबंधित प्रश्न
Can a pendulum clock be used in an earth-satellite?
A hollow sphere filled with water is used as the bob of a pendulum. Assume that the equation for simple pendulum is valid with the distance between the point of suspension and centre of mass of the bob acting as the effective length of the pendulum. If water slowly leaks out of the bob, how will the time period vary?
A platoon of soldiers marches on a road in steps according to the sound of a marching band. The band is stopped and the soldiers are ordered to break the steps while crossing a bridge. Why?
The time period of a particle in simple harmonic motion is equal to the time between consecutive appearances of the particle at a particular point in its motion. This point is
The time period of a particle in simple harmonic motion is equal to the smallest time between the particle acquiring a particular velocity \[\vec{v}\] . The value of v is
A particle moves in a circular path with a continuously increasing speed. Its motion is
A particle moves on the X-axis according to the equation x = x0 sin2 ωt. The motion is simple harmonic
A particle executing SHM crosses points A and B with the same velocity. Having taken 3 s in passing from A to B, it returns to B after another 3 s. The time period is ____________.
The displacement of a particle varies with time according to the relation y = a sin ωt + b cos ωt.
What is the ratio of maxmimum acceleration to the maximum velocity of a simple harmonic oscillator?
