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प्रश्न
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पर्याय
Gauss's Law is valid only for symmetrical charge distributions.
Gauss's Law is valid only for charges placed in vacuum.
The electric field calculated by Gauss's Law is the field due to the charge inside the Gaussian surface.
The flux of the electric field through a closed surface due to all the charges is equal to the flux due to the charges enclosed by the surface.
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उत्तर
The flux of the electric field through a closed surface due to all the charges is equal to the flux due to the charges enclosed by the surface.
The contribution of flux on the closed surface due to the charges lying outside the surface is zero because number of field line entering the closed surface is equal to the number of field lines coming out of the surface so the net contribution of the charge lying outside the closed surface to the flux is zero. Therefore, the net flux through the surface due to the charge lying outside the the closed surface is zero. The contribution that counts is only due to the charges lying within the closed surface.
Thus, the flux of the electric field through a closed surface due to all the charges (inside and outside the surface) is equal to the flux due to the charges enclosed by the surface
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संबंधित प्रश्न
Define electric flux.
Write S.I unit of electric flux.
"The outward electric flux due to charge +Q is independent of the shape and size of the surface which encloses is." Give two reasons to justify this statement.
A thin straight infinitely long conducting wire having charge density λ is enclosed by a cylindrical surface of radius r and length l, its axis coinciding with the length of the wire. Find the expression for the electric flux through the surface of the cylinder.
Following Figure (a) shows an imaginary cube of edge L/2. A uniformly charged rod of length (L) moves towards the left at a small but constant speed `nu.` At t = 0, the left end just touches the centre of the face of the cube opposite it. Which of the graphs shown in the figure (b) represents the flux of the electric field through the cube as the rod goes through it?
The following figure shows a closed surface that intersects a conducting sphere. If a positive charge is placed at point P, the flux of the electric field through the closed surface
If the flux associated with a coil changes at the rate of 360 webers every 4 minutes, then the induced e.m.f. is ______
The electric flux through the surface ______.
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A charged particle q is placed at the centre O of cube of length L (A B C D E F G H). Another same charge q is placed at a distance L from O. Then the electric flux through ABCD is ______.
The total flux through the faces of the cube with side of length a if a charge q is placed at corner A of the cube is ______.
The SI unit of electric flux is ______.
The electric field intensity due to an infinite cylinder of radius R and having charge q per unit length at a distance rir r(r > R) from its axis is ______.
The electric field in a region is given by `bar"E" = 4hat"i" + 10hat"j"` N/C. The flux of this field through a square of 10 cm on a side whose plane is parallel to the XZ plane.
A circular disc of radius 'r' is placed along the plane of paper. A uniform electric field `vec"E"` is also present in the plane of paper. What amount of electric flux is associated with it?
A hollow sphere of radius R has a point charge Q at its centre. Electric flux emanating from it is `phi`. If both the charge and the radius of the sphere are doubled, electric flux emanating from the sphere will ______.
A hollow sphere of radius R has a point charge q at its centre. Electric flux emanating from the sphere is X. How will the electric flux change, if at all, when charge q is replaced by an electric dipole?
An electric field is given by `(6 hat i + 5 hat j + 3 hat k)` N/C. The electric flux through a surface area `30 hat i` m2 lying in YZ-plane (in SI unit) is ______.
