Advertisements
Advertisements
प्रश्न
Given a uniform electric field `vecE=5xx10^3hati`N/C, find the flux of this field through a square of 10 cm on a side whose plane is parallel to the y-z plane. What would be the flux through the same square if the plane makes a 30° angle with the x-axis ?
Advertisements
उत्तर
When the plane is parallel to the y-z plane:
Electric flux, `phi=vecE.vecA`
Here:
`vecE=5xx10^3hati "N/C"`
`vecA=(10cm^2)hati=10^(-2)hatim^2`
`:.phi=(5xx10^3hati).(10^(-2)hati)`
⇒ ϕ =50 Weber
When the plane makes a 30° angle with the x-axis, the area vector makes 60° with the x-axis.
`phi=vecE.vecA`
⇒ϕ=EA cosθ
⇒ϕ=(5×103)(10−2)cos60°
`=>phi=50/2`
⇒ ϕ =25 Weber
APPEARS IN
संबंधित प्रश्न
Define electric flux.
A uniformly charged conducting sphere of 2.4 m diameter has a surface charge density of 80.0 μC/m2.
- Find the charge on the sphere.
- What is the total electric flux leaving the surface of the sphere?
Two charges of magnitudes +4Q and − Q are located at points (a, 0) and (− 3a, 0) respectively. What is the electric flux due to these charges through a sphere of radius ‘2a’ with its centre at the origin?
Following Figure (a) shows an imaginary cube of edge L/2. A uniformly charged rod of length (L) moves towards the left at a small but constant speed `nu.` At t = 0, the left end just touches the centre of the face of the cube opposite it. Which of the graphs shown in the figure (b) represents the flux of the electric field through the cube as the rod goes through it?
Electric charges are distributed in a small volume. The flux of the electric field through a spherical surface of radius 10 cm surrounding the total charge is 25 V m. The flux over a concentric sphere of radius 20 cm will be _____________ .
A uniform electric field of intensity 400 N/C, exists in a certain region. How much flux will cross a given area of 10 cm2 in this region, if the area vector is inclined at 60° to the direction of the field?
Total electric flux coming out of a unit positive charge kept in air is ______.
What will be the total flux through the faces of the cube (figure) with side of length a if a charge q is placed at
- A: a corner of the cube.
- B: mid-point of an edge of the cube.
- C: centre of a face of the cube.
- D: mid-point of B and C.
