Advertisements
Advertisements
प्रश्न
What is the electric flux through a cube of side 1 cm which encloses an electric dipole?
Advertisements
उत्तर
As per the Gauss's law of electrostatics, electric flux through a closed surface is given by
`phi_E=ointvecE.vec(ds)=Q/epsilon_0 `
where
E = Electrostatic field
Q = Total charge enclosed by the surface
∮E=∮E→.ds→=0ε0=0" role="presentation" style="position: relative;">∮E=∮E→.ds→=0ε0=0
∈0 = Absolute electric permittivity of free space
In the given case, cube encloses an electric dipole. Therefore, the total charge enclosed by the cube is zero, i.e. Q = 0.
Therefore, from (i), we have
`phi_E=ointvecE.vec(ds)=0/epsilon_0=0`
APPEARS IN
संबंधित प्रश्न
How does the electric flux due to a point charge enclosed by a spherical Gaussian surface get affected when its radius is increased?
Write S.I unit of electric flux.
Find out the outward flux to a point charge +q placed at the centre of a cube of side ‘a’. Why is it found to be independent of the size and shape of the surface enclosing it? Explain.
A uniformly charged conducting sphere of 2.4 m diameter has a surface charge density of 80.0 μC/m2.
- Find the charge on the sphere.
- What is the total electric flux leaving the surface of the sphere?
Two charges of magnitudes −3Q and + 2Q are located at points (a, 0) and (4a, 0) respectively. What is the electric flux due to these charges through a sphere of radius ‘5a’ with its centre at the origin?
The electric field in a region is given by `vec"E"` = 5 `hatk`N/C. Calculate the electric flux Through a square of side 10.0 cm in the following cases
- The square is along the XY plane
- The square is along XZ plane
- The normal to the square makes an angle of 45° with the Z axis.
A charged particle q is placed at the centre O of cube of length L (A B C D E F G H). Another same charge q is placed at a distance L from O. Then the electric flux through ABCD is ______.
Total electric flux coming out of a unit positive charge kept in air is ______.
A charge Qµc is placed at the centre of a cube the flux coming from any surface will be.
A hollow sphere of radius R has a point charge q at its centre. Electric flux emanating from the sphere is X. How will the electric flux change, if at all, when charge q is replaced by an electric dipole?
