Advertisements
Advertisements
प्रश्न
Advertisements
उत्तर
\[\int \log_{10} x \text{ dx }\]
\[ = \int\frac{\log x}{\log 10}dx\]
\[ = \frac{1}{\log 10}\int 1_{} \cdot \text{ log x dx }\]
` " Taking log x as the first function and 1 as the second function " `
\[ = \frac{1}{\log 10}\left[ \log x \int\text{ 1 dx} - \int\left\{ \frac{d}{dx}\left( \log x \right)\int\text{ 1 dx }\right\}dx \right]\]
\[ = \frac{1}{\log 10}\left[ \log x \cdot x - \int\frac{1}{x} \cdot \text{ x dx } \right]\]
\[ = \frac{1}{\log 10}\left[ x \log x - x \right] + C\]
\[ = \frac{1}{\log 10}\left[ x\left( \log x - 1 \right) \right] + C\]
APPEARS IN
संबंधित प्रश्न
\[\int\left\{ x^2 + e^{\log x}+ \left( \frac{e}{2} \right)^x \right\} dx\]
` ∫ {cosec x} / {"cosec x "- cot x} ` dx
` ∫ {sec x "cosec " x}/{log ( tan x) }` dx
\[\int\frac{x}{\sqrt{8 + x - x^2}} dx\]
\[\int\sqrt{\frac{x}{1 - x}} dx\] is equal to
\[\int\frac{x + 2}{\left( x + 1 \right)^3} \text{ dx }\]
