मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Integrate the following functions w.r.t. x : x.sec2(x2)tan3(x2) - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Integrate the following functions w.r.t. x : `(x.sec^2(x^2))/sqrt(tan^3(x^2)`

बेरीज
Advertisements

उत्तर

Let I = `int (x.sec^2(x^2))/sqrt(tan^3(x^2)).dx`

Put tan(x2) = t

∴ sec2(x2) x 2x dx = dt

∴ `x.sec^2(x^2)dx = dt/(2)`

∴ I = `int (1)/sqrt(t^3).dt/(2)`

= `(1)/(2) int t^(-3/2)dt`

= `(1)/(2).(t^(-1/2))/(-1/2) + c`

= `(-1)/sqrt(t) + c`

= `(-1)/sqrt(tan(x^2)) + c`.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Indefinite Integration - Exercise 3.2 (A) [पृष्ठ ११०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Indefinite Integration
Exercise 3.2 (A) | Q 1.04 | पृष्ठ ११०

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Find: `int(x+3)sqrt(3-4x-x^2dx)`


Evaluate: `int sqrt(tanx)/(sinxcosx) dx`


Integrate the functions:

`(log x)^2/x`


Integrate the functions:

sin (ax + b) cos (ax + b)


Integrate the functions:

`1/(x(log x)^m),  x > 0, m ne 1`


Integrate the functions:

`e^(tan^(-1)x)/(1+x^2)`


Integrate the functions:

`(x^3 sin(tan^(-1) x^4))/(1 + x^8)`


`int (dx)/(sin^2 x cos^2 x)` equals:


Evaluate `int 1/(3+ 2 sinx + cosx) dx`


Evaluate `int (x-1)/(sqrt(x^2 - x)) dx`


\[\int\sqrt{x^2 + x + 1} \text{ dx}\]

\[\int\cos x \sqrt{4 - \sin^2 x}\text{ dx}\]

Write a value of

\[\int e^x \left( \sin x + \cos x \right) \text{ dx}\]

 


 Write a valoue of \[\int \sin^3 x \cos x\ dx\]

 


Write a value of\[\int \cos^4 x \text{ sin x dx }\]


Write a value of

\[\int\frac{1 + \log x}{3 + x \log x} \text{ dx }\] .

Integrate the following functions w.r.t. x : `x^2/sqrt(9 - x^6)`


Integrate the following functions w.r.t. x : `3^(cos^2x) sin 2x`


Evaluate the following : `int (1)/(5 - 4x - 3x^2).dx`


Evaluate the following : `int (1)/sqrt(x^2 + 8x - 20).dx`


Integrate the following functions w.r.t. x : `int (1)/(3 - 2cos 2x).dx`


Evaluate the following integrals : `int (2x + 3)/(2x^2 + 3x - 1).dx`


Evaluate the following integrals : `int sqrt((e^(3x) - e^(2x))/(e^x + 1)).dx`


Choose the correct options from the given alternatives :

`int (cos2x - 1)/(cos2x + 1)*dx` =


Evaluate `int (-2)/(sqrt("5x" - 4) - sqrt("5x" - 2))`dx


If f'(x) = 4x3 − 3x2  + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Choose the correct alternative from the following.

The value of `int "dx"/sqrt"1 - x"` is


Evaluate: `int "e"^sqrt"x"` dx


`int (2(cos^2 x - sin^2 x))/(cos^2 x + sin^2 x)` dx = ______________


If `int 1/(x + x^5)` dx = f(x) + c, then `int x^4/(x + x^5)`dx = ______


`int ("e"^(2x) + "e"^(-2x))/("e"^x)  "d"x`


`int (7x + 9)^13  "d"x` ______ + c


`int "dx"/((sin x + cos x)(2 cos x + sin x))` = ?


`int(5x + 2)/(3x - 4) dx` = ______


`int cos^3x  dx` = ______.


`int(1 - x)^(-2)` dx = `(1 - x)^(-1) + c`


if `f(x) = 4x^3 - 3x^2 + 2x +k, f (0) = - 1 and f (1) = 4, "find " f(x)`


Evaluate `int 1/("x"("x" - 1)) "dx"`


Evaluate the following

`int x^3/sqrt(1+x^4) dx`


Evaluate the following.

`int(1)/(x^2 + 4x - 5)dx`


`int "cosec"^4x  dx` = ______.


Evaluate the following.

`intx sqrt(1 +x^2)  dx`


Evaluate:

`int(cos 2x)/sinx dx`


Evaluate:

`int sin^3x cos^3x  dx`


Evaluate `int(1+x+(x^2)/(2!))dx`


Evaluate.

`int (5x^2 -6x + 3)/(2x -3)dx`


Evaluate the following.

`int 1/ (x^2 + 4x - 5) dx`


Evaluate the following:

`int x^3/(sqrt(1 + x^4)) dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×