मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Integrate the following functions w.r.t. x : x.sec2(x2)tan3(x2)

Advertisements
Advertisements

प्रश्न

Integrate the following functions w.r.t. x : `(x.sec^2(x^2))/sqrt(tan^3(x^2)`

बेरीज
Advertisements

उत्तर

Let I = `int (x.sec^2(x^2))/sqrt(tan^3(x^2)).dx`

Put tan(x2) = t

∴ sec2(x2) x 2x dx = dt

∴ `x.sec^2(x^2)dx = dt/(2)`

∴ I = `int (1)/sqrt(t^3).dt/(2)`

= `(1)/(2) int t^(-3/2)dt`

= `(1)/(2).(t^(-1/2))/(-1/2) + c`

= `(-1)/sqrt(t) + c`

= `(-1)/sqrt(tan(x^2)) + c`.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Indefinite Integration - Exercise 3.2 (A) [पृष्ठ ११०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Indefinite Integration
Exercise 3.2 (A) | Q 1.04 | पृष्ठ ११०

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Evaluate : `int (sinx)/sqrt(36-cos^2x)dx`


Show that:  `int1/(x^2sqrt(a^2+x^2))dx=-1/a^2(sqrt(a^2+x^2)/x)+c`


Evaluate : `int(x-3)sqrt(x^2+3x-18)  dx`


Integrate the functions:

`(1+ log x)^2/x`


Evaluate:  \[\int\frac{x^3 - 1}{x^2} \text{ dx}\]


\[\int\frac{\sin x + 2 \cos x}{2 \sin x + \cos x} \text{ dx }\]


\[\int x \sin^3 x\ dx\]

Evaluate the following integrals : `int sinx/(1 + sinx)dx`


Integrate the following functions w.r.t. x : `(x^n - 1)/sqrt(1 + 4x^n)`


Integrate the following functions w.r.t. x : `(1)/(x(x^3 - 1)`


Integrate the following functions w.r.t. x : `(1)/(2 + 3tanx)`


Integrate the following functions w.r.t. x : `(3e^(2x) + 5)/(4e^(2x) - 5)`


Evaluate the following : `(1)/(4x^2 - 20x + 17)`


Integrate the following functions w.r.t. x : `int (1)/(4 - 5cosx).dx`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2sin x - cosx)dx`


Integrate the following functions w.r.t. x : `int (1)/(3 - 2cos 2x).dx`


Evaluate the following integrals : `int sqrt((x - 7)/(x - 9)).dx`


Evaluate the following integral:

`int (3cosx)/(4sin^2x + 4sinx - 1).dx`


Evaluate the following.

`int "x"^5/("x"^2 + 1)`dx


Evaluate the following.

`int 1/(sqrt"x" + "x")` dx


Choose the correct alternative from the following.

The value of `int "dx"/sqrt"1 - x"` is


Evaluate `int 1/((2"x" + 3))` dx


Evaluate `int "x - 1"/sqrt("x + 4")` dx


Evaluate: `int sqrt(x^2 - 8x + 7)` dx


`int x^x (1 + logx)  "d"x`


`int(1 - x)^(-2) dx` = ______.


Evaluate `int(3x^2 - 5)^2  "d"x`


Evaluate  `int"e"^x (1/x - 1/x^2)  "d"x`


`int sin^-1 x`dx = ?


`int (x^2 + 1)/(x^4 - x^2 + 1)`dx = ?


If `tan^-1x = 2tan^-1((1 - x)/(1 + x))`, then the value of x is ______ 


`int ((x + 1)(x + log x))^4/(3x) "dx" =`______.


The value of `sqrt(2) int (sinx  dx)/(sin(x - π/4))` is ______.


Evaluate `int_(logsqrt(2))^(logsqrt(3)) 1/((e^x + e^-x)(e^x - e^-x)) dx`.


Evaluate the following.

`int 1/(x^2 + 4x - 5)  dx`


Evaluate.

`int (5x^2 - 6x + 3)/(2x - 3) dx`


Evaluate the following.

`int(1)/(x^2 + 4x - 5)dx`


The value of `int ("d"x)/(sqrt(1 - x))` is ______.


Evaluate `int(1+x+(x^2)/(2!))dx`


Evaluate the following:

`int (1) / (x^2 + 4x - 5) dx`


Evaluate `int (1 + "x" + "x"^2/(2!))`dx


Evaluate the following.

`int1/(x^2+4x-5)dx`


What is integration by substitution?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×