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प्रश्न
In Young' s experiment the ratio of intensity at the maxima and minima . in the interference pattern is 36 : 16. What is the ratio of the widths of the two slits?
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उत्तर
`I_(max)/I_(min)=((A_1/A_2+1)/(A_1/A_2-1))^2`
`Let A_1/A_2=r`
`therefore I_(max)/I_(min)=((r+1)/(r-1))^2`
`therefore 36/16=((r+1)/(r-1))^2`
`therefore 6/4=((r+1)/(r-1))`
`therefore r=5/1`
`A_1/A_2=5/1`
Ratio of width `=(A_1/A_2)^2=25/1`
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संबंधित प्रश्न
(i) In Young's double-slit experiment, deduce the condition for (a) constructive and (b) destructive interferences at a point on the screen. Draw a graph showing variation of intensity in the interference pattern against position 'x' on the screen.
(b) Compare the interference pattern observed in Young's double-slit experiment with single-slit diffraction pattern, pointing out three distinguishing features.
Derive an expression for path difference in Young’s double slit experiment and obtain the conditions for constructive and destructive interference at a point on the screen.
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- the least distance from the central maximum where the bright fringes due to both wavelengths coincide.
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- Slits are brought closer to each other.
- Screen is moved away from the slits.
- Red coloured light is replaced with blue coloured light.
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