Advertisements
Advertisements
प्रश्न
In the figure given below, A, B and C are three ammeters. The ammeter B reads 0.5A. (All the ammeters have negligible resistance.)
Calculate:
(i) the readings in the ammeters A and C.
(ii) the total resistance of the circuit.
Advertisements
उत्तर
(i) P.d. across 6 Ω = P. d. across 3 Ω
Or 6 × 0.5 = 3 × ic
Or ic i.e., current passing through the ammeter C is:
`(6 xx 0.5)/3 = 1.0`ampere
(ii) Here, `1/"R" = 1/6 + 1/3 = 3/6 = 1/2`
or R = 2 Ω
∴ Total ressistance of the circuit = 2Ω + R = 2Ω + 2Ω = 4Ω
∴ Current through A = Current passing through B + current passing through C
= 0.5 + 1.0 = 1.5 ampere
संबंधित प्रश्न
What is the unit of electric charge?
If a potential difference of 10 V causes a current of 2 A to flow for 1 minute, how much energy is transferred?
The p.d. across a lamp is 12 V. How many joules of electrical energy are changed into heat and light when:
a charge of 5 C passes through it?
Keeping the potential difference constant, the resistance of a circuit is halved. By how much does the current change?
How does the resistance of a metallic wire depend on its temperature? Explain with reason.
The voltage across a 3Ω resistance is 6 V. How large is the current? What is
the resistance of a filament lamp when a voltage of 3 V across it causes a
current of 0.5 A?
Calculate the current flowing through each of the resistors A and B in the circuit shown in the following figure.
An electric bulb draws 0.5 A current at 3.0 V. Calculate the resistance of the filament of the bulb.
Exercise.
Calculate the amount of charge that would flow in 2 hours through an element of an electric bulb drawing a current of 2.5 A.
Two charged spherical conductors of radius R1 and R2 are connected by a wire. Then the ratio of surface charge densities of the spheres `(σ_1//σ_2 )` is ______.
