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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता ७

In the expression 25 m + 14 M, the type of the terms are ________ terms

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प्रश्न

In the expression 25m + 14n, the type of the terms are ________ terms

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उत्तर

In the expression 25m + 14n, the type of the terms are unlike terms

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पाठ 3: Algebra - Exercise 3.1 [पृष्ठ ५७]

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सामाचीर कलवी Mathematics - Term 1 [English] Class 7 TN Board
पाठ 3 Algebra
Exercise 3.1 | Q 1. (iii) | पृष्ठ ५७

संबंधित प्रश्‍न

State whether a given pair of term is of like or unlike term.

1,100


State whether a given pair of term is of like or unlike term.

`-7x, 5/2 x`


Identify like term in the following:

−xy2, − 4yx2, 8x2, 2xy2, 7y, −11x2, −100x, −11yx, 20x2y, −6x2, y, 2xy, 3x


Take away: 

\[\frac{y^3}{3} + \frac{7}{3} y^2 + \frac{1}{2}y + \frac{1}{2} \text { from } \frac{1}{3} - \frac{5}{3} y^2\]


Take away: 

\[\frac{2}{3}ac - \frac{5}{7}ab + \frac{2}{3}bc\text { from } \frac{3}{2}ab - \frac{7}{4}ac - \frac{5}{6}bc\]


Simplify the following:

\[\left( \frac{1}{3} y^2 - \frac{4}{7}y + 11 \right) - \left( \frac{1}{7}y - 3 + 2 y^2 \right) - \left( \frac{2}{7}y - \frac{2}{3} y^2 + 2 \right)\]


Simplify the following: \[- \frac{1}{2} a^2 b^2 c + \frac{1}{3}a b^2 c - \frac{1}{4}ab c^2 - \frac{1}{5}c b^2 a^2 + \frac{1}{6}c b^2 a - \frac{1}{7} c^2 ab + \frac{1}{8}c a^2 b .\]


In the polynomial, given below, separate the like terms:

3xy, − 4yx2, 2xy2, 2.5x2y, −8yx, −3.2y2x and x2y


Find the product of the terms

3x2y , −3xy3, x2y2


If the area of a square is 36x4y2 then, its side is ____________


Choose the pair of like terms


In an expression, we can add or subtract only ________


Identify the like terms: 12x3y2z, – y3x2z, 4z3y2x, 6x3z2y, – 5y3x2z


Sum of a – b + ab, b + c – bc and c – a – ac is ______.


The product of two terms with like signs is a ______ term.


Sum or difference of two like terms is ______.


–5a2b and –5b2a are ______ terms.


Which option correctly identifies a constant and a variable?


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