Advertisements
Advertisements
प्रश्न
Find the product of the terms
3x2y , −3xy3, x2y2
Advertisements
उत्तर
(3x2y) × (−3xy3) × (x2y2) = (+) × (−) × (+) × (3 × 3 × 1)(x2 × x × x2) × (y × y3 × y2)
= −9x5 y6
APPEARS IN
संबंधित प्रश्न
Take away:
\[\frac{6}{5} x^2 - \frac{4}{5} x^3 + \frac{5}{6} + \frac{3}{2}x \text { from }\frac{x^3}{3} - \frac{5}{2} x^2 + \frac{3}{5}x + \frac{1}{4}\]
Take away:
\[\frac{7}{4} x^3 + \frac{3}{5} x^2 + \frac{1}{2}x + \frac{9}{2}\text { from } \frac{7}{2} - \frac{x}{3} - \frac{x^2}{5}\]
Take away:
\[\frac{y^3}{3} + \frac{7}{3} y^2 + \frac{1}{2}y + \frac{1}{2} \text { from } \frac{1}{3} - \frac{5}{3} y^2\]
In the polynomial, given below, separate the like terms :
y2z3, xy2z3, −5x2yz, −4y2z3, −8xz3y2, 3x2yz and 2z3y2
In the expression 25m + 14n, the type of the terms are ________ terms
Which of the following is a binomial?
The product of two negative terms is a negative term.
The product of one negative and one positive term is a negative term.
3a2b and –7ba2 are ______ terms.
–5a2b and –5b2a are ______ terms.
