Advertisements
Advertisements
प्रश्न
Simplify the following: \[- \frac{1}{2} a^2 b^2 c + \frac{1}{3}a b^2 c - \frac{1}{4}ab c^2 - \frac{1}{5}c b^2 a^2 + \frac{1}{6}c b^2 a - \frac{1}{7} c^2 ab + \frac{1}{8}c a^2 b .\]
Advertisements
उत्तर
\[- \frac{1}{2} a^2 b^2 c + \frac{1}{3}a b^2 c - \frac{1}{4}ab c^2 - \frac{1}{5}c b^2 a^2 + \frac{1}{6}c b^2 a - \frac{1}{7} c^2 ab + \frac{1}{8}c a^2 b\]
\[= - \frac{1}{2} a^2 b^2 c - \frac{1}{5}c b^2 a^2 + \frac{1}{3}a b^2 c + \frac{1}{6}c b^2 a - \frac{1}{4}ab c^2 - \frac{1}{7} c^2 ab + \frac{1}{8}c a^2 b\] (Collecting like terms)
= \[\left( \frac{- 5 - 2}{10} \right) a^2 b^2 c + \left( \frac{2 + 1}{6} \right)c b^2 a^2 + \left( \frac{- 7 - 4}{28} \right) c^2 ab + \frac{1}{8}c a^2 b\]
\[= - \frac{7}{10} a^2 b^2 c + \frac{1}{2}a b^2 c - \frac{11}{28}ab c^2 + \frac{1}{8} a^2 bc\] (Combining like terms)
APPEARS IN
संबंधित प्रश्न
Take away:
\[\frac{y^3}{3} + \frac{7}{3} y^2 + \frac{1}{2}y + \frac{1}{2} \text { from } \frac{1}{3} - \frac{5}{3} y^2\]
Simplify the following:
x2 − 3x + 5 − \[\frac{1}{2}\] (3x2 − 5x + 7)
Find the product of the terms
−2mn, (2m)2, −3mn
The missing terms in the product −3m3n × 9(__) = _________ m4n3
Which of the following is a binomial?
The product of two terms with like signs is a ______ term.
The product of two negative terms is a negative term.
Which of the following is a pair of like terms?
Sum or difference of two like terms is ______.
3a2b and –7ba2 are ______ terms.
