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प्रश्न
Simplify the following: \[- \frac{1}{2} a^2 b^2 c + \frac{1}{3}a b^2 c - \frac{1}{4}ab c^2 - \frac{1}{5}c b^2 a^2 + \frac{1}{6}c b^2 a - \frac{1}{7} c^2 ab + \frac{1}{8}c a^2 b .\]
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उत्तर
\[- \frac{1}{2} a^2 b^2 c + \frac{1}{3}a b^2 c - \frac{1}{4}ab c^2 - \frac{1}{5}c b^2 a^2 + \frac{1}{6}c b^2 a - \frac{1}{7} c^2 ab + \frac{1}{8}c a^2 b\]
\[= - \frac{1}{2} a^2 b^2 c - \frac{1}{5}c b^2 a^2 + \frac{1}{3}a b^2 c + \frac{1}{6}c b^2 a - \frac{1}{4}ab c^2 - \frac{1}{7} c^2 ab + \frac{1}{8}c a^2 b\] (Collecting like terms)
= \[\left( \frac{- 5 - 2}{10} \right) a^2 b^2 c + \left( \frac{2 + 1}{6} \right)c b^2 a^2 + \left( \frac{- 7 - 4}{28} \right) c^2 ab + \frac{1}{8}c a^2 b\]
\[= - \frac{7}{10} a^2 b^2 c + \frac{1}{2}a b^2 c - \frac{11}{28}ab c^2 + \frac{1}{8} a^2 bc\] (Combining like terms)
संबंधित प्रश्न
State whether a given pair of term is of like or unlike term.
`-7x, 5/2 x`
State whether a given pair of term is of like or unlike term.
12xz, 12x2z2
Identify like term in the following:
−xy2, − 4yx2, 8x2, 2xy2, 7y, −11x2, −100x, −11yx, 20x2y, −6x2, y, 2xy, 3x
Take away:
\[\frac{y^3}{3} + \frac{7}{3} y^2 + \frac{1}{2}y + \frac{1}{2} \text { from } \frac{1}{3} - \frac{5}{3} y^2\]
Take away:
\[\frac{2}{3}ac - \frac{5}{7}ab + \frac{2}{3}bc\text { from } \frac{3}{2}ab - \frac{7}{4}ac - \frac{5}{6}bc\]
Choose the pair of like terms
The product of two negative terms is a negative term.
123x2y – 138x2y is a like term of ______.
–5a2b and –5b2a are ______ terms.
In like terms, variables and their powers are the same.
