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प्रश्न
Simplify the following:
\[\frac{11}{2} x^2 y - \frac{9}{4}x y^2 + \frac{1}{4}xy - \frac{1}{14} y^2 x + \frac{1}{15}y x^2 + \frac{1}{2}xy\]
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उत्तर
\[ \frac{11}{2} x^2 y - \frac{9}{4}x y^2 + \frac{1}{4}xy - \frac{1}{14} y^2 x + \frac{1}{15}y x^2 + \frac{1}{2}xy\]
\[= \frac{11}{2} x^2 y + \frac{1}{15}y x^2 - \frac{9}{4}x y^2 - \frac{1}{14} y^2 x + \frac{1}{4}xy + \frac{1}{2}xy\] (Collecting like terms)
= \[\left( \frac{165 + 2}{30} \right) x^2 y + \left( \frac{- 63 - 2}{28} \right)x y^2 + \left( \frac{1 + 2}{4} \right)xy\]
\[= \frac{167}{30} x^2 y - \frac{65}{28} y^2 x + \frac{3}{2}xy\] (Combining like terms)
संबंधित प्रश्न
Simplify the following:
\[\left( \frac{1}{3} y^2 - \frac{4}{7}y + 11 \right) - \left( \frac{1}{7}y - 3 + 2 y^2 \right) - \left( \frac{2}{7}y - \frac{2}{3} y^2 + 2 \right)\]
Simplify the following: \[- \frac{1}{2} a^2 b^2 c + \frac{1}{3}a b^2 c - \frac{1}{4}ab c^2 - \frac{1}{5}c b^2 a^2 + \frac{1}{6}c b^2 a - \frac{1}{7} c^2 ab + \frac{1}{8}c a^2 b .\]
In the polynomial, given below, separate the like terms:
3xy, − 4yx2, 2xy2, 2.5x2y, −8yx, −3.2y2x and x2y
If the area of a square is 36x4y2 then, its side is ____________
Choose the pair of like terms
7a2b and −7ab2 are like terms
Which of the following is a binomial?
123x2y – 138x2y is a like term of ______.
3a2b and –7ba2 are ______ terms.
Which of the following pairs represents "like terms"?
