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प्रश्न
Take away:
\[\frac{5 a^2}{2} + \frac{3 a^3}{2} + \frac{a}{3} - \frac{6}{5} \text { from } \frac{1}{3} a^3 - \frac{3}{4} a^2 - \frac{5}{2}\]
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उत्तर
The difference is given by:
\[\left( \frac{1}{3} a^3 - \frac{3 a^2}{4} - \frac{5}{2} \right) - \left( \frac{5 a^2}{2} + \frac{3 a^3}{2} + \frac{a}{3} - \frac{6}{5} \right)\]
\[ = \frac{1}{3} a^3 - \frac{3 a^2}{4} - \frac{5}{2} - \frac{5 a^2}{2} - \frac{3 a^3}{2} - \frac{a}{3} + \frac{6}{5}\]
\[= \frac{1}{3} a^3 - \frac{3 a^3}{2} - \frac{3 a^2}{4} - \frac{5 a^2}{2} - \frac{a}{3} - \frac{5}{2} + \frac{6}{5}\] (Collecting like terms)
= \[\left( \frac{2 - 9}{6} \right) a^3 + \left( \frac{- 3 - 10}{4} \right) a^2 - \frac{a}{3} + \left( \frac{- 25 + 12}{10} \right)\]
\[= - \frac{7}{6} a^3 - \frac{13}{4} a^2 - \frac{a}{3} - \frac{13}{10}\] (Combining like terms)
संबंधित प्रश्न
Identify like term in the following:
−xy2, − 4yx2, 8x2, 2xy2, 7y, −11x2, −100x, −11yx, 20x2y, −6x2, y, 2xy, 3x
Take away:
\[\frac{7}{4} x^3 + \frac{3}{5} x^2 + \frac{1}{2}x + \frac{9}{2}\text { from } \frac{7}{2} - \frac{x}{3} - \frac{x^2}{5}\]
Take away:
\[\frac{2}{3}ac - \frac{5}{7}ab + \frac{2}{3}bc\text { from } \frac{3}{2}ab - \frac{7}{4}ac - \frac{5}{6}bc\]
In the polynomial, given below, separate the like terms:
3xy, − 4yx2, 2xy2, 2.5x2y, −8yx, −3.2y2x and x2y
In an expression, we can add or subtract only ________
Which of the following is a binomial?
The product of two terms with unlike signs is a ______ term.
123x2y – 138x2y is a like term of ______.
Sum or difference of two like terms is ______.
–5a2b and –5b2a are ______ terms.
