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Question
Simplify the following:
\[\frac{11}{2} x^2 y - \frac{9}{4}x y^2 + \frac{1}{4}xy - \frac{1}{14} y^2 x + \frac{1}{15}y x^2 + \frac{1}{2}xy\]
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Solution
\[ \frac{11}{2} x^2 y - \frac{9}{4}x y^2 + \frac{1}{4}xy - \frac{1}{14} y^2 x + \frac{1}{15}y x^2 + \frac{1}{2}xy\]
\[= \frac{11}{2} x^2 y + \frac{1}{15}y x^2 - \frac{9}{4}x y^2 - \frac{1}{14} y^2 x + \frac{1}{4}xy + \frac{1}{2}xy\] (Collecting like terms)
= \[\left( \frac{165 + 2}{30} \right) x^2 y + \left( \frac{- 63 - 2}{28} \right)x y^2 + \left( \frac{1 + 2}{4} \right)xy\]
\[= \frac{167}{30} x^2 y - \frac{65}{28} y^2 x + \frac{3}{2}xy\] (Combining like terms)
RELATED QUESTIONS
State whether a given pair of term is of like or unlike term.
1,100
Take away:
\[\frac{y^3}{3} + \frac{7}{3} y^2 + \frac{1}{2}y + \frac{1}{2} \text { from } \frac{1}{3} - \frac{5}{3} y^2\]
Take away:
\[\frac{2}{3}ac - \frac{5}{7}ab + \frac{2}{3}bc\text { from } \frac{3}{2}ab - \frac{7}{4}ac - \frac{5}{6}bc\]
Simplify the following: \[- \frac{1}{2} a^2 b^2 c + \frac{1}{3}a b^2 c - \frac{1}{4}ab c^2 - \frac{1}{5}c b^2 a^2 + \frac{1}{6}c b^2 a - \frac{1}{7} c^2 ab + \frac{1}{8}c a^2 b .\]
Find the product of the terms
−2mn, (2m)2, −3mn
The product of two terms with like signs is a ______ term.
The product of one negative and one positive term is a negative term.
Which of the following is a pair of like terms?
Sum or difference of two like terms is ______.
Which option correctly identifies a constant and a variable?
