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प्रश्न
Take away:
\[\frac{2}{3}ac - \frac{5}{7}ab + \frac{2}{3}bc\text { from } \frac{3}{2}ab - \frac{7}{4}ac - \frac{5}{6}bc\]
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उत्तर
The difference is given by:
\[\left( \frac{3}{2}ab - \frac{7}{4}ac - \frac{5}{6}bc \right) - \left( \frac{2}{3}ac - \frac{5}{7}ab + \frac{2}{3}bc \right)\]
\[ = \frac{3}{2}ab-\frac{7}{4}ac-\frac{5}{6}bc-\frac{2}{3}ac+\frac{5}{7}ab-\frac{2}{3}bc\]
\[= \frac{3}{2}ab + \frac{5}{7}ab - \frac{7}{4}ac - \frac{2}{3}ac - \frac{5}{6}bc - \frac{2}{3}bc\] (Collecting like terms )
= \[\left( \frac{21 + 10}{14} \right)ab + \left( \frac{- 21 - 8}{12} \right)ac + \left( \frac{- 5 - 4}{6} \right)bc\]
\[=\frac{31}{14}ab-\frac{29}{12}ac-\frac{3}{2}bc\] (Combining like terms )
संबंधित प्रश्न
Take away:
\[\frac{6}{5} x^2 - \frac{4}{5} x^3 + \frac{5}{6} + \frac{3}{2}x \text { from }\frac{x^3}{3} - \frac{5}{2} x^2 + \frac{3}{5}x + \frac{1}{4}\]
Take away:
\[\frac{7}{4} x^3 + \frac{3}{5} x^2 + \frac{1}{2}x + \frac{9}{2}\text { from } \frac{7}{2} - \frac{x}{3} - \frac{x^2}{5}\]
Simplify the following:
\[\left( \frac{1}{3} y^2 - \frac{4}{7}y + 11 \right) - \left( \frac{1}{7}y - 3 + 2 y^2 \right) - \left( \frac{2}{7}y - \frac{2}{3} y^2 + 2 \right)\]
Simplify the following: \[- \frac{1}{2} a^2 b^2 c + \frac{1}{3}a b^2 c - \frac{1}{4}ab c^2 - \frac{1}{5}c b^2 a^2 + \frac{1}{6}c b^2 a - \frac{1}{7} c^2 ab + \frac{1}{8}c a^2 b .\]
Find the product of the terms
3x2y , −3xy3, x2y2
In an expression, we can add or subtract only ________
Sum of a – b + ab, b + c – bc and c – a – ac is ______.
The product of two terms with unlike signs is a ______ term.
123x2y – 138x2y is a like term of ______.
In an algebraic expression, terms are separated by which of the following signs?
