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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता ७

Identify the like terms: 12x3y2z, – y3x2z, 4z3y2x, 6x3z2y, – 5y3x2z

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प्रश्न

Identify the like terms: 12x3y2z, – y3x2z, 4z3y2x, 6x3z2y, – 5y3x2z

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उत्तर

– y3x2z and – 5y3x2z are like terms.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Algebra - Exercise 3.3 [पृष्ठ ६२]

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सामाचीर कलवी Mathematics - Term 2 [English] Class 7 TN Board
पाठ 3 Algebra
Exercise 3.3 | Q 5 | पृष्ठ ६२

संबंधित प्रश्‍न

State whether a given pair of term is of like or unlike term.

14xy, 42yx


State whether a given pair of term is of like or unlike term.

4m2p, 4mp2


Identify like term in the following:

10pq, 7p, 8q, −p2q2, −7qp, −100q, −23, 12q2p2, −5p2, 41, 2405p, 78qp, 13p2q, qp2, 701p2


Take away:

\[\frac{6}{5} x^2 - \frac{4}{5} x^3 + \frac{5}{6} + \frac{3}{2}x \text { from  }\frac{x^3}{3} - \frac{5}{2} x^2 + \frac{3}{5}x + \frac{1}{4}\]


Simplify the following:

\[\frac{11}{2} x^2 y - \frac{9}{4}x y^2 + \frac{1}{4}xy - \frac{1}{14} y^2 x + \frac{1}{15}y x^2 + \frac{1}{2}xy\]


Simplify the following: \[- \frac{1}{2} a^2 b^2 c + \frac{1}{3}a b^2 c - \frac{1}{4}ab c^2 - \frac{1}{5}c b^2 a^2 + \frac{1}{6}c b^2 a - \frac{1}{7} c^2 ab + \frac{1}{8}c a^2 b .\]


Find the product of the terms

3x2y , −3xy3, x2y2


2pq and – 7qp are like terms


Identify the like terms among the following:

7x, 5y, −8x, 12y, 6z, z, −12x, −9y, 11z


7a2b and −7ab2 are like terms


Like term as 4m3n2 is ______.


Which of the following is a binomial?


Which of the following are like terms?


The product of two terms with like signs is a ______ term.


The product of two negative terms is a negative term.


Which of the following is a pair of like terms?


123x2y – 138x2y is a like term of ______.


Like terms in the expression n(n + 1) + 6(n – 1) are ______ and ______.


The unlike terms in perimeters of following figures are ______ and ______.


In like terms, variables and their powers are the same.


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