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प्रश्न
In the diagram, a narrow beam of white light is incident on a right-angled isosceles prism. The critical angle of the material of prism for the yellow colour of white light is 45°. Complete the diagram to show the path of blue, yellow, and red colours of white light till they emerge out of the prism.
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उत्तर
The completed diagram is shown below:
The critical angle for yellow light is given to be 45°. Since μblue > μyellow and μred < μyellow so the critical angle for blue light will be less than 45° and for red light will be more than 45°.
संबंधित प्रश्न
Study the following ray diagram:
In this diagram, the angle of incidence, the angle of emergence and the angle of deviation respectively have been represented by
(A) y, p, z
(B) x, q, z
(C) p, y, z
(D) p, z, y
Which of the following coloured light has the least speed in glass prism?
(a) violet
(b) yellow
(c) red
(d) green
The speed of light in air or vacuum is
The diagram below shows the path taken by a narrow beam of yellow monochromatic light passing through an equiangular glass prism. If the yellow light is replaced by a narrow beam of white light incident at the same angle, draw another diagram to show the passage of white light through the prism and label it to show the effect of prism on the white light.
Draw a labeled ray diagram to illustrate the dispersion of a narrow beam of white light when it passes through a glass prism.
An object AB is placed in front of a convex lens as shown in fig. 4. Complete the ray diagram and obtain the image formed and state the nature of the image.
A wave has wavelength 50Å of State the speed in vacuum.
Which characteristic property of light is responsible for the blue colour of the sky?
Which one of the following is involved for the formation of rainbow in the sky?
Observe the given diagram and answer the questions:
- Name the process shown in the figure.
- Name the colour that deviates the most.
- Name the colour that deviates the least.
- Name any one phenomenon in nature which is based on the above process.
- Define ‘spectrum’.
