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In Order to Have a Current in a Long Wire, It Should Be Connected to a Battery Or Some Such Device. Can We Obtain the Magnetic Due to a Straight,

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प्रश्न

In order to have a current in a long wire, it should be connected to a battery or some such device. Can we obtain the magnetic due to a straight, long wire by using Ampere's law without mentioning this other part of the circuit? 

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उत्तर

We can obtain a magnetic field due to a straight, long wire using Ampere's law by mentioning the current flowing in the wire, without emphasising on the source of the current in the wire. To apply Ampere's circuital law, we need to have a constant current flowing in the wire, irrespective of its source.

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पाठ 35: Magnetic Field due to a Current - Short Answers [पृष्ठ २४८]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 35 Magnetic Field due to a Current
Short Answers | Q 10 | पृष्ठ २४८

संबंधित प्रश्‍न

Using Ampere’s circuital law, obtain the expression for the magnetic field due to a long solenoid at a point inside the solenoid on its axis ?


A long, straight wire carries a current. Is Ampere's law valid for a loop that does not enclose the wire, or that encloses the wire but is not circular?


A hollow tube is carrying an electric current along its length distributed uniformly over its surface. The magnetic field
(a) increases linearly from the axis to the surface
(b) is constant inside the tube
(c) is zero at the axis
(d) is zero just outside the tube.


A long, cylindrical tube of inner and outer  radii a and b carries a current i distributed uniformly over its cross section. Find the magnitude of the magnitude filed at a point (a) just inside the tube (b) just outside the tube.


Using Ampere's circuital law, obtain an expression for the magnetic flux density 'B' at a point 'X' at a perpendicular distance 'r' from a long current-carrying conductor.
(Statement of the law is not required).


Define ampere.


Find the magnetic field due to a long straight conductor using Ampere’s circuital law.


Calculate the magnetic field inside and outside of the long solenoid using Ampere’s circuital law


The magnetic field around a long straight current carrying wire is ______.

A long solenoid has a radius a and number of turns per unit length n. If it carries a current i, then the magnetic field on its axis is directly proportional to ______.

Which of the following is the correct definition of ampere?

Ampere’s circuital law is given by _______.


Ampere's circuital law is used to find out ______


Two concentric and coplanar circular loops P and Q have their radii in the ratio 2:3. Loop Q carries a current 9 A in the anticlockwise direction. For the magnetic field to be zero at the common centre, loop P must carry ______.


A long straight wire of radius 'a' carries a steady current 'I'. The current is uniformly distributed across its area of cross-section. The ratio of the magnitude of magnetic field `vecB_1` at `a/2` and `vecB_2` at distance 2a is ______.


Read the following paragraph and answer the questions.

Consider the experimental set-up shown in the figure. This jumping ring experiment is an outstanding demonstration of some simple laws of Physics. A conducting non-magnetic ring is placed over the vertical core of a solenoid. When current is passed through the solenoid, the ring is thrown off.

  1. Explain the reason for the jumping of the ring when the switch is closed in the circuit.
  2. What will happen if the terminals of the battery are reversed and the switch is closed? Explain.
  3. Explain the two laws that help us understand this phenomenon.

When current flowing through a solenoid decreases from 5A to 0 in 20 milliseconds, an emf of 500V is induced in it.

  1. What is this phenomenon called?
  2. Calculate coefficient of self-inductance of the solenoid.

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