Advertisements
Advertisements
प्रश्न
If two adjacent angles of a parallelogram are (5x – 5)° and (10x + 35)°, then the ratio of these angles is ______.
पर्याय
1 : 3
2 : 3
1 : 4
1 : 2
Advertisements
उत्तर
If two adjacent angles of a parallelogram are (5x – 5)° and (10x + 35)°, then the ratio of these angles is 1 : 3.
Explanation:
We know that, adjacent angles of a parallelogram are supplementary, i.e. their sum equals 180°.
∴ (5x – 5) + (10x + 35) = 180°
⇒ 15x + 30° = 180°
⇒ 15x = 150°
⇒ x = 10°
Thus, the angles are (5 × 10 – 5) and (10 × 10 + 35), i.e. 45° and 135°.
Hence, the required ratio is 45° : 135°, i.e. 1 : 3.
APPEARS IN
संबंधित प्रश्न
Can a quadrilateral ABCD be a parallelogram if AB = DC = 8 cm, AD = 4 cm and BC = 4.4 cm?
The adjacent figure HOPE is a parallelogram. Find the angle measures x, y and z. State the properties you use to find them.

Find the measure of ∠P and ∠S, if `bar(SP) || bar(RQ)` in the following figure. (If you find m∠R, is there more than one method to find m∠P?).

Name the quadrilaterals whose diagonals bisect each other
If the ratio of measures of two adjacent angles of a parallelogram is 1 : 2, find the measures of all angles of the parallelogram.
In the given figure, `square`ABCD is a parallelogram. Point E is on the ray AB such that BE = AB then prove that line ED bisects seg BC at point F.

Construct ☐ BARC such that l(BA) = l(BC) = 4.2 cm, l(AC) = 6.0 cm, l(AR) = l(CR) = 5.6 cm
ABCD is a parallelogram. What kind of quadrilateral is it if: AC is perpendicular to BD but is not equal to it?
In parallelogram ABCD, E is the mid-point of AD and F is the mid-point of BC. Prove that BFDE is a parallelogram.
The given figure shows parallelogram ABCD. Points M and N lie in diagonal BD such that DM = BN.

Prove that:
(i) ∆DMC = ∆BNA and so CM = AN
(ii) ∆AMD = ∆CNB and so AM CN
(iii) ANCM is a parallelogram.
