Question

If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: `"log" sqrt(72)`

Answer 1

`"log" sqrt(72)`

= `"log"(72)^(1/2)`

= `(1)/(2)"log"72`

= `(1)/(2)"log"(2^3 xx 3^2)`

= `(1)/(2)"log"2^3 + (1)/(2)"log"3^2`

= `(3)/(2)"log"2 + (2)/(2)"log"3`

= `(3)/(2)"log"2 + "log"3`

= `(3/2 xx 0.3010) + 0.4771`
= 0.9286.