Advertisements
Advertisements
प्रश्न
Given: log3 m = x and log3 n = y.
Express 32x - 3 in terms of m.
Advertisements
उत्तर
Given that log3m = x and log3n = y
⇒ 3x = m and 3y = n
Consider the given expression :
32x - 3
= 32x . 3-3
=` 3^(2x) . 1/3^3`
= `3^(2x)/3^3`
= `(3^x)^2/3^3`
= `m^2/27`
Therefore, 32x - 3 = `m^2/27`
APPEARS IN
संबंधित प्रश्न
Given 3log x + `1/2`log y = 2, express y in term of x.
If log 2 = 0.3010 and log 3 = 0.4771 ; find the value of : log 1.2
If log 2 = 0.3010 and log 3 = 0.4771; find the value of : log 15
Prove that : (log a)2 - (log b)2 = log `(( a )/( b ))` . Log (ab)
Express the following in terms of log 5 and/or log 2: log80
Express the following in terms of log 2 and log 3: `"log"(26)/(51) - "log"(91)/(119)`
If log 16 = a, log 9 = b and log 5 = c, evaluate the following in terms of a, b, c: log 2.25
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: log45
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: log540
If 2 log y - log x - 3 = 0, express x in terms of y.
