Advertisements
Advertisements
प्रश्न
If 2 log y - log x - 3 = 0, express x in terms of y.
Advertisements
उत्तर
2log - logx - 3 = 0
⇒ logx = 2logy - 3
⇒ logx = logy2 - 3log10 ...[∵ log10 = 1]
⇒ logx = logy2 - log103
⇒ logx = `"log"(y^2/1000)`
∴ x = `y^2/(1000)`.
APPEARS IN
संबंधित प्रश्न
Given 3log x + `1/2`log y = 2, express y in term of x.
If log102 = a and log103 = b ; express each of the following in terms of 'a' and 'b': log 2.25
If log10 a = b, find 103b - 2 in terms of a.
Given log x = 2m - n , log y = n - 2m and log z = 3m - 2n , find in terms of m and n, the value of log `(x^2y^3 ) /(z^4) `.
Express the following in terms of log 2 and log 3: log 144
Express the following in terms of log 2 and log 3: `"log" root(3)(144)`
Simplify the following:
`12"log" (3)/(2) + 7 "log" (125)/(27) - 5 "log" (25)/(36) - 7 "log" 25 + "log" (16)/(3)`
If 2 log x + 1 = 40, find: x
If log1025 = x and log1027 = y; evaluate without using logarithmic tables, in terms of x and y: log103
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: log540
