Advertisements
Advertisements
Question
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: `"log" sqrt(72)`
Advertisements
Solution
`"log" sqrt(72)`
= `"log"(72)^(1/2)`
= `(1)/(2)"log"72`
= `(1)/(2)"log"(2^3 xx 3^2)`
= `(1)/(2)"log"2^3 + (1)/(2)"log"3^2`
= `(3)/(2)"log"2 + (2)/(2)"log"3`
= `(3)/(2)"log"2 + "log"3`
= `(3/2 xx 0.3010) + 0.4771`
= 0.9286.
APPEARS IN
RELATED QUESTIONS
If log 27 = 1.431, find the value of : log 300
Express the following in terms of log 2 and log 3: log 54
Express the following in terms of log 5 and/or log 2: log160
Express the following in terms of log 2 and log 3: `"log" root(4)(648)`
Write the logarithmic equation for:
F = `"G"("m"_1"m"_2)/"d"^2`
Write the logarithmic equation for:
E = `(1)/(2)"m v"^2`
Express the following as a single logarithm:
`2"log" (16)/(25) - 3 "log" (8)/(5) + "log" 90`
Express the following as a single logarithm:
`"log"(81)/(8) - 2"log"(3)/(5) + 3"log"(2)/(5) + "log"(25)/(9)`
If log 16 = a, log 9 = b and log 5 = c, evaluate the following in terms of a, b, c: log 75
If log 27 = 1.431, find the value of the following: log300
