Advertisements
Advertisements
प्रश्न
If 2 log x + 1 = 40, find: x
Advertisements
उत्तर
2 log x + 1 = 40
⇒ 2log x = 39
⇒ logx2 = 39
⇒ x2 = 1039
⇒ x = `10^(39/2)`.
APPEARS IN
संबंधित प्रश्न
If 3( log 5 - log 3 ) - ( log 5 - 2 log 6 ) = 2 - log x, find x.
If log10 8 = 0.90; find the value of : log 0.125
Express the following in terms of log 5 and/or log 2: log20
Express the following in terms of log 2 and log 3: `"log" root(3)(144)`
Express the following as a single logarithm:
`2"log" (16)/(25) - 3 "log" (8)/(5) + "log" 90`
Express the following as a single logarithm:
`"log"(81)/(8) - 2"log"(3)/(5) + 3"log"(2)/(5) + "log"(25)/(9)`
Simplify the following:
`2 "log" 5 +"log" 8 - (1)/(2) "log" 4`
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: `"log" sqrt(72)`
If x2 + y2 = 6xy, prove that `"log"((x - y)/2) = (1)/(2)` (log x + log y)
Simplify: log b ÷ log b2
